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Year 10 Coordinates: Quadrants, Midpoints and Distance Worksheet — Level 3 — Answers

Answer sheet with worked solutions for the Year 10 geometry worksheet.

Success TutoringWorksheetsAnswer sheetYear 10 · Mathematics · Geometry

Year 10 Coordinates: Quadrants, Midpoints and Distance Worksheet — Level 3 — Answers

Midpoint = (average of the x-values, average of the y-values). Distance: use Pythagoras with the horizontal and vertical changes.

1.Find the distance between (−6, 2) and (−5, −4), correct to 1 decimal place.

Answer: 6.1

  1. Horizontal change = 1, vertical change = 6
  2. d = √(12 + 62) = √37
  3. = 6.1
2.Find the midpoint of the segment joining (−6, −6) and (−8, −5).

Answer: (−7, −5.5)

  1. x: (−6 + (−8)) ÷ 2 = −7
  2. y: (−6 + (−5)) ÷ 2 = −5.5
3.Find the distance between (0, −1) and (5, −13).

Answer: 13

  1. Horizontal change = 5, vertical change = 12
  2. d = √(52 + 122) = √169
  3. = 13
4.Find the midpoint of the segment joining (5, 0) and (−2, 5).

Answer: (1.5, 2.5)

  1. x: (5 + (−2)) ÷ 2 = 1.5
  2. y: (0 + 5) ÷ 2 = 2.5
5.Find the midpoint of the segment joining (5, −5) and (1, 5).

Answer: (3, 0)

  1. x: (5 + 1) ÷ 2 = 3
  2. y: (−5 + 5) ÷ 2 = 0
6.Find the distance between (5, −4) and (10, −7), correct to 1 decimal place.

Answer: 5.8

  1. Horizontal change = 5, vertical change = 3
  2. d = √(52 + 32) = √34
  3. = 5.8
7.Find the distance between (3, 6) and (−2, 8), correct to 1 decimal place.

Answer: 5.4

  1. Horizontal change = 5, vertical change = 2
  2. d = √(52 + 22) = √29
  3. = 5.4
8.Find the distance between (−4, −4) and (5, 3), correct to 1 decimal place.

Answer: 11.4

  1. Horizontal change = 9, vertical change = 7
  2. d = √(92 + 72) = √130
  3. = 11.4
9.Find the distance between (−1, 3) and (−9, −12).

Answer: 17

  1. Horizontal change = 8, vertical change = 15
  2. d = √(82 + 152) = √289
  3. = 17
10.Find the distance between (−3, 3) and (−4, 5), correct to 1 decimal place.

Answer: 2.2

  1. Horizontal change = 1, vertical change = 2
  2. d = √(12 + 22) = √5
  3. = 2.2
11.Find the distance between (−1, −6) and (6, 3), correct to 1 decimal place.

Answer: 11.4

  1. Horizontal change = 7, vertical change = 9
  2. d = √(72 + 92) = √130
  3. = 11.4
12.Find the midpoint of the segment joining (7, 4) and (−5, −8).

Answer: (1, −2)

  1. x: (7 + (−5)) ÷ 2 = 1
  2. y: (4 + (−8)) ÷ 2 = −2
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