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Year 10 Coordinates: Quadrants, Midpoints and Distance Worksheet — Level 3 — Practice Set 2 — Answers

Answer sheet with worked solutions for the Year 10 geometry worksheet.

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Success TutoringWorksheetsAnswer sheetYear 10 · Mathematics · Geometry

Year 10 Coordinates: Quadrants, Midpoints and Distance Worksheet — Level 3 — Practice Set 2 — Answers

Midpoint = (average of the x-values, average of the y-values). Distance: use Pythagoras with the horizontal and vertical changes.

1.Find the midpoint of the segment joining (−9, −2) and (0, 8).

Answer: (−4.5, 3)

  1. x: (−9 + 0) ÷ 2 = −4.5
  2. y: (−2 + 8) ÷ 2 = 3
2.Find the distance between (6, 5) and (12, 8), correct to 1 decimal place.

Answer: 6.7

  1. Horizontal change = 6, vertical change = 3
  2. d = √(62 + 32) = √45
  3. = 6.7
3.Find the midpoint of the segment joining (1, −2) and (−3, 5).

Answer: (−1, 1.5)

  1. x: (1 + (−3)) ÷ 2 = −1
  2. y: (−2 + 5) ÷ 2 = 1.5
4.Find the midpoint of the segment joining (0, −8) and (8, −1).

Answer: (4, −4.5)

  1. x: (0 + 8) ÷ 2 = 4
  2. y: (−8 + (−1)) ÷ 2 = −4.5
5.Find the midpoint of the segment joining (7, −8) and (−6, 8).

Answer: (0.5, 0)

  1. x: (7 + (−6)) ÷ 2 = 0.5
  2. y: (−8 + 8) ÷ 2 = 0
6.Find the distance between (1, 2) and (−2, −4), correct to 1 decimal place.

Answer: 6.7

  1. Horizontal change = 3, vertical change = 6
  2. d = √(32 + 62) = √45
  3. = 6.7
7.Find the distance between (4, −2) and (2, −5), correct to 1 decimal place.

Answer: 3.6

  1. Horizontal change = 2, vertical change = 3
  2. d = √(22 + 32) = √13
  3. = 3.6
8.Find the distance between (−1, −1) and (−9, −16).

Answer: 17

  1. Horizontal change = 8, vertical change = 15
  2. d = √(82 + 152) = √289
  3. = 17
9.Find the distance between (0, −3) and (−4, 6), correct to 1 decimal place.

Answer: 9.8

  1. Horizontal change = 4, vertical change = 9
  2. d = √(42 + 92) = √97
  3. = 9.8
10.Find the midpoint of the segment joining (−8, 1) and (6, −7).

Answer: (−1, −3)

  1. x: (−8 + 6) ÷ 2 = −1
  2. y: (1 + (−7)) ÷ 2 = −3
11.Find the distance between (−3, 4) and (5, −3), correct to 1 decimal place.

Answer: 10.6

  1. Horizontal change = 8, vertical change = 7
  2. d = √(82 + 72) = √113
  3. = 10.6
12.Find the distance between (4, 6) and (−4, 8), correct to 1 decimal place.

Answer: 8.2

  1. Horizontal change = 8, vertical change = 2
  2. d = √(82 + 22) = √68
  3. = 8.2
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