What you need to know
A quadratic is an expression whose highest power is x2. A quadratic equation in standard form is ax[sup 2] + bx + c = 0. Solving it means finding the values of x that make it true; there can be two, one or no real solutions. The main method is to factorise and then use the null factor law: if two things multiply to give 0, at least one of them must be 0.
Expanding (the reverse of factorising). (x + 3)(x + 5) = x2 + 5x + 3x + 15 = x2 + 8x + 15. Notice that 3 + 5 = 8 (the middle coefficient) and 3 × 5 = 15 (the constant). Factorising runs this backwards.
Factorising x[sup 2] + bx + c. Find two numbers that multiply to give c and add to give b.
Three sum-and-product examples
- x2 + 7x + 12: numbers 3 and 4 (3 × 4 = 12, 3 + 4 = 7) → (x + 3)(x + 4).
- x2 − 5x + 6: numbers −2 and −3 (product 6, sum −5) → (x − 2)(x − 3).
- x2 − 2x − 15: numbers −5 and 3 (product −15, sum −2) → (x − 5)(x + 3).
| Special case | Pattern | Example |
|---|
| Common factor | Take out the HCF first | 3x2 + 6x = 3x(x + 2) |
| Difference of two squares | a2 − b2 = (a − b)(a + b) | x2 − 25 = (x − 5)(x + 5) |
| Perfect square | a2 + 2ab + b2 = (a + b)2 | x2 + 6x + 9 = (x + 3)2 |
Solve x2 − 2x − 15 = 0
- Factorise: (x − 5)(x + 3) = 0.
- Null factor law: x − 5 = 0 or x + 3 = 0.
- x = 5 or x = −3.
- Check x = 5: 25 − 10 − 15 = 0. Check x = −3: 9 + 6 − 15 = 0.
Solve x2 = 5x
- Make one side zero: x2 − 5x = 0.
- Common factor: x(x − 5) = 0.
- x = 0 or x = 5.
Common mistake: dividing both sides of x2 = 5x by x to get x = 5. That throws away the solution x = 0. Always move everything to one side and factorise instead. Related trap: the equation must equal 0 before you use the null factor law — (x − 1)(x + 2) = 4 does not mean x − 1 = 4 or x + 2 = 4. Expand, rearrange to equal 0, then factorise again.
The quadratic formula. When a quadratic will not factorise easily, use x = [frac −b ± √(b[sup 2] − 4ac)/2a]. The part under the square root, b2 − 4ac, is the discriminant: positive means two solutions, zero means one solution, negative means no real solutions.
Solve 2x2 + 3x − 2 = 0
- a = 2, b = 3, c = −2.
- Discriminant: 32 − 4 × 2 × (−2) = 9 + 16 = 25.
- x = −3 ± √254 = −3 ± 54.
- x = 24 = [frac 1/2] or x = −84 = −2.
- (This one also factorises: (2x − 1)(x + 2) = 0 gives the same answers.)
Check yourself
- Factorise x2 + 9x + 20.
- Factorise x2 − 49.
- Solve x2 + 3x − 10 = 0.
- Solve x2 − 6x + 9 = 0.
- Solve 4x2 − 12x = 0.
- Solve x2 + 2x − 1 = 0 using the formula (exact and to 2 decimal places).
Answers: 1. (x + 4)(x + 5) 2. (x − 7)(x + 7) 3. (x + 5)(x − 2) = 0, so x = −5 or x = 2 4. (x − 3)2 = 0, so x = 3 5. 4x(x − 3) = 0, so x = 0 or x = 3 6. x = −2 ± √82 = −1 ± √2, so x ≈ 0.41 or x ≈ −2.41