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Year 6 Circumference and Area of Circles Worksheet — Level 3 — Practice Set 2 — Answers

Answer sheet with worked solutions for the Year 6 area & perimeter worksheet.

Success TutoringWorksheetsAnswer sheetYear 6 · Mathematics · Area & Perimeter

Year 6 Circumference and Area of Circles Worksheet — Level 3 — Practice Set 2 — Answers

Show your working. Use the π button on your calculator and round to 1 decimal place unless told otherwise.

1.Find the area of a semicircle with a radius of 5 cm, correct to 1 decimal place.

Answer: 39.3 cm2

  1. A = ½ × π × r2 = ½ × π × 25
  2. ≈ 39.3 cm2
2.Find the area of a semicircle with a radius of 17 cm, correct to 1 decimal place.

Answer: 454.0 cm2

  1. A = ½ × π × r2 = ½ × π × 289
  2. ≈ 454.0 cm2
3.Find the area of a semicircle with a radius of 20 cm, correct to 1 decimal place.

Answer: 628.3 cm2

  1. A = ½ × π × r2 = ½ × π × 400
  2. ≈ 628.3 cm2
4.A circle has a circumference of 26π cm. Find its radius and its area (leave the area in terms of π).

Answer: r = 13 cm; A = 169π cm2

  1. C = 2πr, so 2πr = 26π
  2. r = 13 cm
  3. A = πr2 = 169π cm2
5.Find the area of a semicircle with a radius of 4 cm, correct to 1 decimal place.

Answer: 25.1 cm2

  1. A = ½ × π × r2 = ½ × π × 16
  2. ≈ 25.1 cm2
6.Find the area of a semicircle with a radius of 14 cm, correct to 1 decimal place.

Answer: 307.9 cm2

  1. A = ½ × π × r2 = ½ × π × 196
  2. ≈ 307.9 cm2
7.A circle has a diameter of 38 cm. Find its area, correct to 1 decimal place.

Answer: 1134.1 cm2

  1. r = 38 ÷ 2 = 19 cm
  2. A = π × r2 = π × 192 = π × 361
  3. ≈ 1134.1 cm2
8.Find the area of a semicircle with a radius of 12 cm, correct to 1 decimal place.

Answer: 226.2 cm2

  1. A = ½ × π × r2 = ½ × π × 144
  2. ≈ 226.2 cm2
9.A circle has a radius of 6 cm. Find its area, correct to 1 decimal place.

Answer: 113.1 cm2

  1. A = π × r2 = π × 62 = π × 36
  2. ≈ 113.1 cm2
10.A circle has a circumference of 22π cm. Find its radius and its area (leave the area in terms of π).

Answer: r = 11 cm; A = 121π cm2

  1. C = 2πr, so 2πr = 22π
  2. r = 11 cm
  3. A = πr2 = 121π cm2
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