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Year 6 Coordinates: Quadrants, Midpoints and Distance Worksheet — Level 3 — Answers

Answer sheet with worked solutions for the Year 6 geometry worksheet.

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Success TutoringWorksheetsAnswer sheetYear 6 · Mathematics · Geometry

Year 6 Coordinates: Quadrants, Midpoints and Distance Worksheet — Level 3 — Answers

Midpoint = (average of the x-values, average of the y-values). Distance: use Pythagoras with the horizontal and vertical changes.

1.Find the distance between (6, −5) and (2, 1), correct to 1 decimal place.

Answer: 7.2

  1. Horizontal change = 4, vertical change = 6
  2. d = √(42 + 62) = √52
  3. = 7.2
2.Find the distance between (−1, −2) and (4, 10).

Answer: 13

  1. Horizontal change = 5, vertical change = 12
  2. d = √(52 + 122) = √169
  3. = 13
3.Find the distance between (−6, −1) and (−4, 2), correct to 1 decimal place.

Answer: 3.6

  1. Horizontal change = 2, vertical change = 3
  2. d = √(22 + 32) = √13
  3. = 3.6
4.Find the distance between (1, −2) and (4, 3), correct to 1 decimal place.

Answer: 5.8

  1. Horizontal change = 3, vertical change = 5
  2. d = √(32 + 52) = √34
  3. = 5.8
5.Find the distance between (−5, 6) and (−13, −9).

Answer: 17

  1. Horizontal change = 8, vertical change = 15
  2. d = √(82 + 152) = √289
  3. = 17
6.Find the midpoint of the segment joining (3, −9) and (−8, 9).

Answer: (−2.5, 0)

  1. x: (3 + (−8)) ÷ 2 = −2.5
  2. y: (−9 + 9) ÷ 2 = 0
7.Find the midpoint of the segment joining (−1, 1) and (9, 8).

Answer: (4, 4.5)

  1. x: (−1 + 9) ÷ 2 = 4
  2. y: (1 + 8) ÷ 2 = 4.5
8.Find the distance between (3, 2) and (−2, −10).

Answer: 13

  1. Horizontal change = 5, vertical change = 12
  2. d = √(52 + 122) = √169
  3. = 13
9.Find the midpoint of the segment joining (−5, −2) and (−9, −2).

Answer: (−7, −2)

  1. x: (−5 + (−9)) ÷ 2 = −7
  2. y: (−2 + (−2)) ÷ 2 = −2
10.Find the midpoint of the segment joining (1, 2) and (−6, −3).

Answer: (−2.5, −0.5)

  1. x: (1 + (−6)) ÷ 2 = −2.5
  2. y: (2 + (−3)) ÷ 2 = −0.5
11.Find the distance between (6, 1) and (15, −11).

Answer: 15

  1. Horizontal change = 9, vertical change = 12
  2. d = √(92 + 122) = √225
  3. = 15
12.Find the distance between (2, 3) and (−4, 11).

Answer: 10

  1. Horizontal change = 6, vertical change = 8
  2. d = √(62 + 82) = √100
  3. = 10
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