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Year 6 Coordinates: Quadrants, Midpoints and Distance Worksheet — Level 3 — Practice Set 4 — Answers

Answer sheet with worked solutions for the Year 6 geometry worksheet.

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Success TutoringWorksheetsAnswer sheetYear 6 · Mathematics · Geometry

Year 6 Coordinates: Quadrants, Midpoints and Distance Worksheet — Level 3 — Practice Set 4 — Answers

Midpoint = (average of the x-values, average of the y-values). Distance: use Pythagoras with the horizontal and vertical changes.

1.Find the distance between (−4, 2) and (−10, −3), correct to 1 decimal place.

Answer: 7.8

  1. Horizontal change = 6, vertical change = 5
  2. d = √(62 + 52) = √61
  3. = 7.8
2.Find the midpoint of the segment joining (8, 7) and (−5, −5).

Answer: (1.5, 1)

  1. x: (8 + (−5)) ÷ 2 = 1.5
  2. y: (7 + (−5)) ÷ 2 = 1
3.Find the midpoint of the segment joining (−5, 1) and (−2, 8).

Answer: (−3.5, 4.5)

  1. x: (−5 + (−2)) ÷ 2 = −3.5
  2. y: (1 + 8) ÷ 2 = 4.5
4.Find the midpoint of the segment joining (−5, −5) and (9, 0).

Answer: (2, −2.5)

  1. x: (−5 + 9) ÷ 2 = 2
  2. y: (−5 + 0) ÷ 2 = −2.5
5.Find the midpoint of the segment joining (−6, 8) and (−2, −3).

Answer: (−4, 2.5)

  1. x: (−6 + (−2)) ÷ 2 = −4
  2. y: (8 + (−3)) ÷ 2 = 2.5
6.Find the distance between (2, −1) and (5, −5).

Answer: 5

  1. Horizontal change = 3, vertical change = 4
  2. d = √(32 + 42) = √25
  3. = 5
7.Find the midpoint of the segment joining (−9, 3) and (7, 7).

Answer: (−1, 5)

  1. x: (−9 + 7) ÷ 2 = −1
  2. y: (3 + 7) ÷ 2 = 5
8.Find the midpoint of the segment joining (0, −8) and (0, −4).

Answer: (0, −6)

  1. x: (0 + 0) ÷ 2 = 0
  2. y: (−8 + (−4)) ÷ 2 = −6
9.Find the midpoint of the segment joining (2, 0) and (3, 5).

Answer: (2.5, 2.5)

  1. x: (2 + 3) ÷ 2 = 2.5
  2. y: (0 + 5) ÷ 2 = 2.5
10.Find the distance between (−2, −6) and (1, −2).

Answer: 5

  1. Horizontal change = 3, vertical change = 4
  2. d = √(32 + 42) = √25
  3. = 5
11.Find the midpoint of the segment joining (−3, 1) and (0, 1).

Answer: (−1.5, 1)

  1. x: (−3 + 0) ÷ 2 = −1.5
  2. y: (1 + 1) ÷ 2 = 1
12.Find the distance between (−2, 0) and (−4, −7), correct to 1 decimal place.

Answer: 7.3

  1. Horizontal change = 2, vertical change = 7
  2. d = √(22 + 72) = √53
  3. = 7.3
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