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Year 7 Circumference and Area of Circles Worksheet — Level 3 — Practice Set 4 — Answers

Answer sheet with worked solutions for the Year 7 area & perimeter worksheet.

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Success TutoringWorksheetsAnswer sheetYear 7 · Mathematics · Area & Perimeter

Year 7 Circumference and Area of Circles Worksheet — Level 3 — Practice Set 4 — Answers

Show your working. Use the π button on your calculator and round to 1 decimal place unless told otherwise.

1.A circle has a diameter of 8 cm. Find its area, correct to 1 decimal place.

Answer: 50.3 cm2

  1. r = 8 ÷ 2 = 4 cm
  2. A = π × r2 = π × 42 = π × 16
  3. ≈ 50.3 cm2
2.Find the area of a semicircle with a radius of 14 cm, correct to 1 decimal place.

Answer: 307.9 cm2

  1. A = ½ × π × r2 = ½ × π × 196
  2. ≈ 307.9 cm2
3.Find the area of a semicircle with a radius of 10 cm, correct to 1 decimal place.

Answer: 157.1 cm2

  1. A = ½ × π × r2 = ½ × π × 100
  2. ≈ 157.1 cm2
4.A circle has a radius of 17 cm. Find its area, correct to 1 decimal place.

Answer: 907.9 cm2

  1. A = π × r2 = π × 172 = π × 289
  2. ≈ 907.9 cm2
5.A circle has a circumference of 22π cm. Find its radius and its area (leave the area in terms of π).

Answer: r = 11 cm; A = 121π cm2

  1. C = 2πr, so 2πr = 22π
  2. r = 11 cm
  3. A = πr2 = 121π cm2
6.A circle has a radius of 9 cm. Find its area, correct to 1 decimal place.

Answer: 254.5 cm2

  1. A = π × r2 = π × 92 = π × 81
  2. ≈ 254.5 cm2
7.Find the area of a semicircle with a radius of 11 cm, correct to 1 decimal place.

Answer: 190.1 cm2

  1. A = ½ × π × r2 = ½ × π × 121
  2. ≈ 190.1 cm2
8.A circle has a radius of 8 cm. Find its area, correct to 1 decimal place.

Answer: 201.1 cm2

  1. A = π × r2 = π × 82 = π × 64
  2. ≈ 201.1 cm2
9.A circle has a circumference of 28π cm. Find its radius and its area (leave the area in terms of π).

Answer: r = 14 cm; A = 196π cm2

  1. C = 2πr, so 2πr = 28π
  2. r = 14 cm
  3. A = πr2 = 196π cm2
10.A circle has a circumference of 30π cm. Find its radius and its area (leave the area in terms of π).

Answer: r = 15 cm; A = 225π cm2

  1. C = 2πr, so 2πr = 30π
  2. r = 15 cm
  3. A = πr2 = 225π cm2
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