Year 7 Coordinates: Quadrants, Midpoints and Distance Worksheet — Level 3 — Answers
Answer sheet with worked solutions for the Year 7 geometry worksheet.
Year 7 Coordinates: Quadrants, Midpoints and Distance Worksheet — Level 3 — Answers
Midpoint = (average of the x-values, average of the y-values). Distance: use Pythagoras with the horizontal and vertical changes.
1.Find the midpoint of the segment joining (−9, 6) and (4, 4).
Answer: (−2.5, 5)
- x: (−9 + 4) ÷ 2 = −2.5
- y: (6 + 4) ÷ 2 = 5
2.Find the midpoint of the segment joining (−3, 0) and (2, −9).
Answer: (−0.5, −4.5)
- x: (−3 + 2) ÷ 2 = −0.5
- y: (0 + (−9)) ÷ 2 = −4.5
3.Find the midpoint of the segment joining (7, 9) and (−8, 4).
Answer: (−0.5, 6.5)
- x: (7 + (−8)) ÷ 2 = −0.5
- y: (9 + 4) ÷ 2 = 6.5
4.Find the midpoint of the segment joining (−9, 1) and (−7, 7).
Answer: (−8, 4)
- x: (−9 + (−7)) ÷ 2 = −8
- y: (1 + 7) ÷ 2 = 4
5.Find the midpoint of the segment joining (7, 5) and (1, −7).
Answer: (4, −1)
- x: (7 + 1) ÷ 2 = 4
- y: (5 + (−7)) ÷ 2 = −1
6.Find the midpoint of the segment joining (−4, 2) and (1, 8).
Answer: (−1.5, 5)
- x: (−4 + 1) ÷ 2 = −1.5
- y: (2 + 8) ÷ 2 = 5
7.Find the midpoint of the segment joining (−6, −5) and (−3, 8).
Answer: (−4.5, 1.5)
- x: (−6 + (−3)) ÷ 2 = −4.5
- y: (−5 + 8) ÷ 2 = 1.5
8.Find the distance between (5, −3) and (7, −9), correct to 1 decimal place.
Answer: 6.3
- Horizontal change = 2, vertical change = 6
- d = √(22 + 62) = √40
- = 6.3
9.Find the distance between (6, 4) and (3, 8).
Answer: 5
- Horizontal change = 3, vertical change = 4
- d = √(32 + 42) = √25
- = 5
10.Find the distance between (3, −6) and (−5, 9).
Answer: 17
- Horizontal change = 8, vertical change = 15
- d = √(82 + 152) = √289
- = 17
11.Find the midpoint of the segment joining (7, −5) and (−3, 9).
Answer: (2, 2)
- x: (7 + (−3)) ÷ 2 = 2
- y: (−5 + 9) ÷ 2 = 2
12.Find the midpoint of the segment joining (−1, 5) and (8, 6).
Answer: (3.5, 5.5)
- x: (−1 + 8) ÷ 2 = 3.5
- y: (5 + 6) ÷ 2 = 5.5
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