Year 7 Coordinates: Quadrants, Midpoints and Distance Worksheet — Level 3 — Practice Set 2 — Answers
Answer sheet with worked solutions for the Year 7 geometry worksheet.
Year 7 Coordinates: Quadrants, Midpoints and Distance Worksheet — Level 3 — Practice Set 2 — Answers
Midpoint = (average of the x-values, average of the y-values). Distance: use Pythagoras with the horizontal and vertical changes.
1.Find the distance between (3, −2) and (−3, 6).
Answer: 10
- Horizontal change = 6, vertical change = 8
- d = √(62 + 82) = √100
- = 10
2.Find the distance between (−1, −4) and (−9, −19).
Answer: 17
- Horizontal change = 8, vertical change = 15
- d = √(82 + 152) = √289
- = 17
3.Find the distance between (1, −3) and (−5, 5).
Answer: 10
- Horizontal change = 6, vertical change = 8
- d = √(62 + 82) = √100
- = 10
4.Find the midpoint of the segment joining (−6, 5) and (5, 1).
Answer: (−0.5, 3)
- x: (−6 + 5) ÷ 2 = −0.5
- y: (5 + 1) ÷ 2 = 3
5.Find the distance between (−1, −2) and (−4, 2).
Answer: 5
- Horizontal change = 3, vertical change = 4
- d = √(32 + 42) = √25
- = 5
6.Find the distance between (1, 0) and (4, 4).
Answer: 5
- Horizontal change = 3, vertical change = 4
- d = √(32 + 42) = √25
- = 5
7.Find the midpoint of the segment joining (−1, 9) and (−5, −3).
Answer: (−3, 3)
- x: (−1 + (−5)) ÷ 2 = −3
- y: (9 + (−3)) ÷ 2 = 3
8.Find the midpoint of the segment joining (7, 3) and (9, −6).
Answer: (8, −1.5)
- x: (7 + 9) ÷ 2 = 8
- y: (3 + (−6)) ÷ 2 = −1.5
9.Find the distance between (2, −4) and (−1, 0).
Answer: 5
- Horizontal change = 3, vertical change = 4
- d = √(32 + 42) = √25
- = 5
10.Find the distance between (4, 4) and (12, −11).
Answer: 17
- Horizontal change = 8, vertical change = 15
- d = √(82 + 152) = √289
- = 17
11.Find the distance between (0, 5) and (3, 1).
Answer: 5
- Horizontal change = 3, vertical change = 4
- d = √(32 + 42) = √25
- = 5
12.Find the midpoint of the segment joining (3, 5) and (−3, −2).
Answer: (0, 1.5)
- x: (3 + (−3)) ÷ 2 = 0
- y: (5 + (−2)) ÷ 2 = 1.5
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