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Year 8 Coordinates: Quadrants, Midpoints and Distance Worksheet — Level 3 — Answers

Answer sheet with worked solutions for the Year 8 geometry worksheet.

Success TutoringWorksheetsAnswer sheetYear 8 · Mathematics · Geometry

Year 8 Coordinates: Quadrants, Midpoints and Distance Worksheet — Level 3 — Answers

Midpoint = (average of the x-values, average of the y-values). Distance: use Pythagoras with the horizontal and vertical changes.

1.Find the midpoint of the segment joining (−9, 6) and (1, 8).

Answer: (−4, 7)

  1. x: (−9 + 1) ÷ 2 = −4
  2. y: (6 + 8) ÷ 2 = 7
2.Find the midpoint of the segment joining (−5, −8) and (−6, 9).

Answer: (−5.5, 0.5)

  1. x: (−5 + (−6)) ÷ 2 = −5.5
  2. y: (−8 + 9) ÷ 2 = 0.5
3.Find the midpoint of the segment joining (7, 0) and (9, 9).

Answer: (8, 4.5)

  1. x: (7 + 9) ÷ 2 = 8
  2. y: (0 + 9) ÷ 2 = 4.5
4.Find the distance between (−3, 3) and (−11, 18).

Answer: 17

  1. Horizontal change = 8, vertical change = 15
  2. d = √(82 + 152) = √289
  3. = 17
5.Find the midpoint of the segment joining (4, 4) and (−7, −3).

Answer: (−1.5, 0.5)

  1. x: (4 + (−7)) ÷ 2 = −1.5
  2. y: (4 + (−3)) ÷ 2 = 0.5
6.Find the distance between (5, 5) and (3, −4), correct to 1 decimal place.

Answer: 9.2

  1. Horizontal change = 2, vertical change = 9
  2. d = √(22 + 92) = √85
  3. = 9.2
7.Find the midpoint of the segment joining (−4, −9) and (8, 6).

Answer: (2, −1.5)

  1. x: (−4 + 8) ÷ 2 = 2
  2. y: (−9 + 6) ÷ 2 = −1.5
8.Find the distance between (−4, 3) and (2, 11).

Answer: 10

  1. Horizontal change = 6, vertical change = 8
  2. d = √(62 + 82) = √100
  3. = 10
9.Find the distance between (5, 6) and (14, 18).

Answer: 15

  1. Horizontal change = 9, vertical change = 12
  2. d = √(92 + 122) = √225
  3. = 15
10.Find the distance between (−6, 4) and (0, −4).

Answer: 10

  1. Horizontal change = 6, vertical change = 8
  2. d = √(62 + 82) = √100
  3. = 10
11.Find the distance between (1, −6) and (−7, 9).

Answer: 17

  1. Horizontal change = 8, vertical change = 15
  2. d = √(82 + 152) = √289
  3. = 17
12.Find the distance between (−5, 2) and (3, −13).

Answer: 17

  1. Horizontal change = 8, vertical change = 15
  2. d = √(82 + 152) = √289
  3. = 17
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