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Year 8 Gradient and Linear Equations Worksheet — Level 1 — Practice Set 2 — Answers

Answer sheet with worked solutions for the Year 8 linear relationships & graphs worksheet.

Success TutoringWorksheetsAnswer sheetYear 8 · Mathematics · Linear Relationships & Graphs

Year 8 Gradient and Linear Equations Worksheet — Level 1 — Practice Set 2 — Answers

Show your working. Gradient = rise ÷ run; the equation of a line can be written as y = (gradient)x + (y-intercept).

1.Find the gradient of the line through (−5, −4) and (−9, 8).

Answer: −3

  1. gradient = rise ÷ run = (8 − (−4)) ÷ (−9 − (−5))
  2. = 12 ÷ −4 = −3
2.Find the gradient of the line through (−4, −6) and (−3, −3).

Answer: 3

  1. gradient = rise ÷ run = (−3 − (−6)) ÷ (−3 − (−4))
  2. = 3 ÷ 1 = 3
3.For the line y = −6x − 3, write the gradient and the y-intercept.

Answer: gradient −6; y-intercept −3

In y = (gradient)x + (y-intercept), the number multiplying x is the gradient and the constant is where the line crosses the y-axis.

4.For the line y = 5x + 1, write the gradient and the y-intercept.

Answer: gradient 5; y-intercept 1

In y = (gradient)x + (y-intercept), the number multiplying x is the gradient and the constant is where the line crosses the y-axis.

5.For the line y = 3x − 2, write the gradient and the y-intercept.

Answer: gradient 3; y-intercept −2

In y = (gradient)x + (y-intercept), the number multiplying x is the gradient and the constant is where the line crosses the y-axis.

6.Find the gradient of the line through (−5, 6) and (−2, 0).

Answer: −2

  1. gradient = rise ÷ run = (0 − 6) ÷ (−2 − (−5))
  2. = −6 ÷ 3 = −2
7.Find the gradient of the line through (−3, −2) and (−6, −8).

Answer: 2

  1. gradient = rise ÷ run = (−8 − (−2)) ÷ (−6 − (−3))
  2. = −6 ÷ −3 = 2
8.For the line y = 6x − 6, write the gradient and the y-intercept.

Answer: gradient 6; y-intercept −6

In y = (gradient)x + (y-intercept), the number multiplying x is the gradient and the constant is where the line crosses the y-axis.

9.Find the gradient of the line through (0, −4) and (3, −7).

Answer: −1

  1. gradient = rise ÷ run = (−7 − (−4)) ÷ (3 − 0)
  2. = −3 ÷ 3 = −1
10.For the line y = 2x − 7, write the gradient and the y-intercept.

Answer: gradient 2; y-intercept −7

In y = (gradient)x + (y-intercept), the number multiplying x is the gradient and the constant is where the line crosses the y-axis.

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