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Year 8 Gradient and Linear Equations Worksheet — Level 2 — Practice Set 2 — Answers

Answer sheet with worked solutions for the Year 8 linear relationships & graphs worksheet.

Success TutoringWorksheetsAnswer sheetYear 8 · Mathematics · Linear Relationships & Graphs

Year 8 Gradient and Linear Equations Worksheet — Level 2 — Practice Set 2 — Answers

Show your working. Gradient = rise ÷ run; the equation of a line can be written as y = (gradient)x + (y-intercept).

1.Find the gradient of the line through (5, −6) and (9, 1).

Answer:

  1. gradient = rise ÷ run = (1 − (−6)) ÷ (9 − 5)
  2. = 7 ÷ 4 =
2.A line has a gradient of −3 and passes through (−4, 19). Find its equation.

Answer: y = −3x + 7

  1. y = −3x + (y-intercept)
  2. 19 = −3 × (−4) + (y-intercept)
  3. y-intercept = 19 − 12 = 7
  4. y = −3x + 7
3.For the line y = 2x + 4, write the gradient and the y-intercept.

Answer: gradient 2; y-intercept 4

In y = (gradient)x + (y-intercept), the number multiplying x is the gradient and the constant is where the line crosses the y-axis.

4.Find the gradient of the line through (−6, 0) and (−9, −9).

Answer: 3

  1. gradient = rise ÷ run = (−9 − 0) ÷ (−9 − (−6))
  2. = −9 ÷ −3 = 3
5.For the line y = −3x + 1, write the gradient and the y-intercept.

Answer: gradient −3; y-intercept 1

In y = (gradient)x + (y-intercept), the number multiplying x is the gradient and the constant is where the line crosses the y-axis.

6.Find the gradient of the line through (−5, 3) and (−9, 2).

Answer:

  1. gradient = rise ÷ run = (2 − 3) ÷ (−9 − (−5))
  2. = −1 ÷ −4 =
7.Find the gradient of the line through (3, −3) and (6, −5).

Answer: −

  1. gradient = rise ÷ run = (−5 − (−3)) ÷ (6 − 3)
  2. = −2 ÷ 3 = −
8.Find the gradient of the line through (2, 0) and (0, −3).

Answer:

  1. gradient = rise ÷ run = (−3 − 0) ÷ (0 − 2)
  2. = −3 ÷ −2 =
9.For the line y = 6x + 2, write the gradient and the y-intercept.

Answer: gradient 6; y-intercept 2

In y = (gradient)x + (y-intercept), the number multiplying x is the gradient and the constant is where the line crosses the y-axis.

10.For the line y = 2x, write the gradient and the y-intercept.

Answer: gradient 2; y-intercept 0

In y = (gradient)x + (y-intercept), the number multiplying x is the gradient and the constant is where the line crosses the y-axis.

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