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Year 9 Coordinates: Quadrants, Midpoints and Distance Worksheet — Level 3 — Answers

Answer sheet with worked solutions for the Year 9 geometry worksheet.

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Success TutoringWorksheetsAnswer sheetYear 9 · Mathematics · Geometry

Year 9 Coordinates: Quadrants, Midpoints and Distance Worksheet — Level 3 — Answers

Midpoint = (average of the x-values, average of the y-values). Distance: use Pythagoras with the horizontal and vertical changes.

1.Find the midpoint of the segment joining (3, 8) and (8, −2).

Answer: (5.5, 3)

  1. x: (3 + 8) ÷ 2 = 5.5
  2. y: (8 + (−2)) ÷ 2 = 3
2.Find the midpoint of the segment joining (−7, −3) and (4, −8).

Answer: (−1.5, −5.5)

  1. x: (−7 + 4) ÷ 2 = −1.5
  2. y: (−3 + (−8)) ÷ 2 = −5.5
3.Find the distance between (−3, −5) and (−11, 10).

Answer: 17

  1. Horizontal change = 8, vertical change = 15
  2. d = √(82 + 152) = √289
  3. = 17
4.Find the distance between (6, −4) and (12, −12).

Answer: 10

  1. Horizontal change = 6, vertical change = 8
  2. d = √(62 + 82) = √100
  3. = 10
5.Find the midpoint of the segment joining (−6, −1) and (1, −8).

Answer: (−2.5, −4.5)

  1. x: (−6 + 1) ÷ 2 = −2.5
  2. y: (−1 + (−8)) ÷ 2 = −4.5
6.Find the midpoint of the segment joining (−6, 9) and (−5, −7).

Answer: (−5.5, 1)

  1. x: (−6 + (−5)) ÷ 2 = −5.5
  2. y: (9 + (−7)) ÷ 2 = 1
7.Find the midpoint of the segment joining (1, 2) and (6, 4).

Answer: (3.5, 3)

  1. x: (1 + 6) ÷ 2 = 3.5
  2. y: (2 + 4) ÷ 2 = 3
8.Find the midpoint of the segment joining (−1, 9) and (9, −5).

Answer: (4, 2)

  1. x: (−1 + 9) ÷ 2 = 4
  2. y: (9 + (−5)) ÷ 2 = 2
9.Find the distance between (−5, 0) and (4, −12).

Answer: 15

  1. Horizontal change = 9, vertical change = 12
  2. d = √(92 + 122) = √225
  3. = 15
10.Find the distance between (1, −4) and (6, −7), correct to 1 decimal place.

Answer: 5.8

  1. Horizontal change = 5, vertical change = 3
  2. d = √(52 + 32) = √34
  3. = 5.8
11.Find the midpoint of the segment joining (−2, −1) and (8, 2).

Answer: (3, 0.5)

  1. x: (−2 + 8) ÷ 2 = 3
  2. y: (−1 + 2) ÷ 2 = 0.5
12.Find the distance between (−1, 0) and (−3, 6), correct to 1 decimal place.

Answer: 6.3

  1. Horizontal change = 2, vertical change = 6
  2. d = √(22 + 62) = √40
  3. = 6.3
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