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Year 9 Coordinates: Quadrants, Midpoints and Distance Worksheet — Level 3 — Practice Set 2 — Answers

Answer sheet with worked solutions for the Year 9 geometry worksheet.

Success TutoringWorksheetsAnswer sheetYear 9 · Mathematics · Geometry

Year 9 Coordinates: Quadrants, Midpoints and Distance Worksheet — Level 3 — Practice Set 2 — Answers

Midpoint = (average of the x-values, average of the y-values). Distance: use Pythagoras with the horizontal and vertical changes.

1.Find the midpoint of the segment joining (4, 0) and (−1, 8).

Answer: (1.5, 4)

  1. x: (4 + (−1)) ÷ 2 = 1.5
  2. y: (0 + 8) ÷ 2 = 4
2.Find the distance between (−1, 5) and (−2, 14), correct to 1 decimal place.

Answer: 9.1

  1. Horizontal change = 1, vertical change = 9
  2. d = √(12 + 92) = √82
  3. = 9.1
3.Find the midpoint of the segment joining (−7, 8) and (−3, 9).

Answer: (−5, 8.5)

  1. x: (−7 + (−3)) ÷ 2 = −5
  2. y: (8 + 9) ÷ 2 = 8.5
4.Find the distance between (3, 1) and (1, 6), correct to 1 decimal place.

Answer: 5.4

  1. Horizontal change = 2, vertical change = 5
  2. d = √(22 + 52) = √29
  3. = 5.4
5.Find the midpoint of the segment joining (−3, −2) and (−4, 9).

Answer: (−3.5, 3.5)

  1. x: (−3 + (−4)) ÷ 2 = −3.5
  2. y: (−2 + 9) ÷ 2 = 3.5
6.Find the distance between (−1, 2) and (−6, −10).

Answer: 13

  1. Horizontal change = 5, vertical change = 12
  2. d = √(52 + 122) = √169
  3. = 13
7.Find the midpoint of the segment joining (6, −5) and (−9, 8).

Answer: (−1.5, 1.5)

  1. x: (6 + (−9)) ÷ 2 = −1.5
  2. y: (−5 + 8) ÷ 2 = 1.5
8.Find the distance between (2, 2) and (−3, −10).

Answer: 13

  1. Horizontal change = 5, vertical change = 12
  2. d = √(52 + 122) = √169
  3. = 13
9.Find the distance between (1, 1) and (0, 6), correct to 1 decimal place.

Answer: 5.1

  1. Horizontal change = 1, vertical change = 5
  2. d = √(12 + 52) = √26
  3. = 5.1
10.Find the distance between (4, 3) and (3, 7), correct to 1 decimal place.

Answer: 4.1

  1. Horizontal change = 1, vertical change = 4
  2. d = √(12 + 42) = √17
  3. = 4.1
11.Find the distance between (−3, 0) and (4, −8), correct to 1 decimal place.

Answer: 10.6

  1. Horizontal change = 7, vertical change = 8
  2. d = √(72 + 82) = √113
  3. = 10.6
12.Find the midpoint of the segment joining (0, 1) and (−4, 8).

Answer: (−2, 4.5)

  1. x: (0 + (−4)) ÷ 2 = −2
  2. y: (1 + 8) ÷ 2 = 4.5
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