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Year 9 Gradient and Linear Equations Worksheet — Level 1 — Practice Set 2 — Answers

Answer sheet with worked solutions for the Year 9 linear relationships & graphs worksheet.

Success TutoringWorksheetsAnswer sheetYear 9 · Mathematics · Linear Relationships & Graphs

Year 9 Gradient and Linear Equations Worksheet — Level 1 — Practice Set 2 — Answers

Show your working. Gradient = rise ÷ run; the equation of a line can be written as y = (gradient)x + (y-intercept).

1.Find the gradient of the line through (−5, −3) and (−2, 3).

Answer: 2

  1. gradient = rise ÷ run = (3 − (−3)) ÷ (−2 − (−5))
  2. = 6 ÷ 3 = 2
2.For the line y = 4x − 7, write the gradient and the y-intercept.

Answer: gradient 4; y-intercept −7

In y = (gradient)x + (y-intercept), the number multiplying x is the gradient and the constant is where the line crosses the y-axis.

3.Find the gradient of the line through (−5, −4) and (−10, −19).

Answer: 3

  1. gradient = rise ÷ run = (−19 − (−4)) ÷ (−10 − (−5))
  2. = −15 ÷ −5 = 3
4.Find the gradient of the line through (−5, 5) and (0, 10).

Answer: 1

  1. gradient = rise ÷ run = (10 − 5) ÷ (0 − (−5))
  2. = 5 ÷ 5 = 1
5.Find the gradient of the line through (4, −3) and (2, −1).

Answer: −1

  1. gradient = rise ÷ run = (−1 − (−3)) ÷ (2 − 4)
  2. = 2 ÷ −2 = −1
6.Find the gradient of the line through (−6, 5) and (−4, 1).

Answer: −2

  1. gradient = rise ÷ run = (1 − 5) ÷ (−4 − (−6))
  2. = −4 ÷ 2 = −2
7.Find the gradient of the line through (4, −5) and (5, −7).

Answer: −2

  1. gradient = rise ÷ run = (−7 − (−5)) ÷ (5 − 4)
  2. = −2 ÷ 1 = −2
8.Find the gradient of the line through (−4, −4) and (−1, −7).

Answer: −1

  1. gradient = rise ÷ run = (−7 − (−4)) ÷ (−1 − (−4))
  2. = −3 ÷ 3 = −1
9.For the line y = −3x + 5, write the gradient and the y-intercept.

Answer: gradient −3; y-intercept 5

In y = (gradient)x + (y-intercept), the number multiplying x is the gradient and the constant is where the line crosses the y-axis.

10.For the line y = −4x − 9, write the gradient and the y-intercept.

Answer: gradient −4; y-intercept −9

In y = (gradient)x + (y-intercept), the number multiplying x is the gradient and the constant is where the line crosses the y-axis.

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