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Year 9 Gradient and Linear Equations Worksheet — Level 2 — Practice Set 4 — Answers

Answer sheet with worked solutions for the Year 9 linear relationships & graphs worksheet.

Success TutoringWorksheetsAnswer sheetYear 9 · Mathematics · Linear Relationships & Graphs

Year 9 Gradient and Linear Equations Worksheet — Level 2 — Practice Set 4 — Answers

Show your working. Gradient = rise ÷ run; the equation of a line can be written as y = (gradient)x + (y-intercept).

1.A line has a gradient of −3 and passes through (0, 8). Find its equation.

Answer: y = −3x + 8

  1. y = −3x + (y-intercept)
  2. 8 = −3 × 0 + (y-intercept)
  3. y-intercept = 8 − 0 = 8
  4. y = −3x + 8
2.Find the gradient of the line through (−6, −2) and (−11, 6).

Answer: −

  1. gradient = rise ÷ run = (6 − (−2)) ÷ (−11 − (−6))
  2. = 8 ÷ −5 = −
3.A line has a gradient of 4 and passes through (3, 8). Find its equation.

Answer: y = 4x − 4

  1. y = 4x + (y-intercept)
  2. 8 = 4 × 3 + (y-intercept)
  3. y-intercept = 8 − 12 = −4
  4. y = 4x − 4
4.Find the gradient of the line through (6, 1) and (5, 3).

Answer: −2

  1. gradient = rise ÷ run = (3 − 1) ÷ (5 − 6)
  2. = 2 ÷ −1 = −2
5.For the line y = −5x − 4, write the gradient and the y-intercept.

Answer: gradient −5; y-intercept −4

In y = (gradient)x + (y-intercept), the number multiplying x is the gradient and the constant is where the line crosses the y-axis.

6.Find the gradient of the line through (5, 2) and (6, 6).

Answer: 4

  1. gradient = rise ÷ run = (6 − 2) ÷ (6 − 5)
  2. = 4 ÷ 1 = 4
7.Find the gradient of the line through (0, 4) and (4, 11).

Answer:

  1. gradient = rise ÷ run = (11 − 4) ÷ (4 − 0)
  2. = 7 ÷ 4 =
8.For the line y = −3x + 5, write the gradient and the y-intercept.

Answer: gradient −3; y-intercept 5

In y = (gradient)x + (y-intercept), the number multiplying x is the gradient and the constant is where the line crosses the y-axis.

9.A line has a gradient of −5 and passes through (−3, 14). Find its equation.

Answer: y = −5x − 1

  1. y = −5x + (y-intercept)
  2. 14 = −5 × (−3) + (y-intercept)
  3. y-intercept = 14 − 15 = −1
  4. y = −5x − 1
10.For the line y = 5x + 3, write the gradient and the y-intercept.

Answer: gradient 5; y-intercept 3

In y = (gradient)x + (y-intercept), the number multiplying x is the gradient and the constant is where the line crosses the y-axis.

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