Year 9 Trigonometry (Finding Sides) Worksheet — Level 2 — Practice Set 2 — Answers
Answer sheet with worked solutions for the Year 9 trigonometry worksheet.
Year 9 Trigonometry (Finding Sides) Worksheet — Level 2 — Practice Set 2 — Answers
Label the sides (opposite, adjacent, hypotenuse), choose the ratio (SOH CAH TOA), then solve.
1.In a right-angled triangle, the hypotenuse is 16 cm and one angle is 46°. Find the side adjacent to the 46° angle, to 1 decimal place.
Answer: 11.1 cm
- cos 46° = adjacent ÷ hypotenuse
- adjacent = 16 × cos 46°
- ≈ 11.1
2.In a right-angled triangle, the hypotenuse is 11 cm and one angle is 64°. Find the side adjacent to the 64° angle, to 1 decimal place.
Answer: 4.8 cm
- cos 64° = adjacent ÷ hypotenuse
- adjacent = 11 × cos 64°
- ≈ 4.8
3.In a right-angled triangle, the hypotenuse is 12 cm and one angle is 20°. Find the side adjacent to the 20° angle, to 1 decimal place.
Answer: 11.3 cm
- cos 20° = adjacent ÷ hypotenuse
- adjacent = 12 × cos 20°
- ≈ 11.3
4.In a right-angled triangle, the hypotenuse is 5 cm and one angle is 39°. Find the side adjacent to the 39° angle, to 1 decimal place.
Answer: 3.9 cm
- cos 39° = adjacent ÷ hypotenuse
- adjacent = 5 × cos 39°
- ≈ 3.9
5.In a right-angled triangle, the hypotenuse is 22 cm and one angle is 44°. Find the side adjacent to the 44° angle, to 1 decimal place.
Answer: 15.8 cm
- cos 44° = adjacent ÷ hypotenuse
- adjacent = 22 × cos 44°
- ≈ 15.8
6.In a right-angled triangle, the hypotenuse is 9 cm and one angle is 49°. Find the side adjacent to the 49° angle, to 1 decimal place.
Answer: 5.9 cm
- cos 49° = adjacent ÷ hypotenuse
- adjacent = 9 × cos 49°
- ≈ 5.9
7.In a right-angled triangle, the hypotenuse is 28 cm and one angle is 41°. Find the side adjacent to the 41° angle, to 1 decimal place.
Answer: 21.1 cm
- cos 41° = adjacent ÷ hypotenuse
- adjacent = 28 × cos 41°
- ≈ 21.1
8.In a right-angled triangle, the hypotenuse is 24 cm and one angle is 50°. Find the side adjacent to the 50° angle, to 1 decimal place.
Answer: 15.4 cm
- cos 50° = adjacent ÷ hypotenuse
- adjacent = 24 × cos 50°
- ≈ 15.4
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