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Year 10 Circumference and Area of Circles Worksheet — Level 3 — Practice Set 3 — Answers

Answer sheet with worked solutions for the Year 10 area & perimeter worksheet.

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Success TutoringWorksheetsAnswer sheetYear 10 · Mathematics · Area & Perimeter

Year 10 Circumference and Area of Circles Worksheet — Level 3 — Practice Set 3 — Answers

Show your working. Use the π button on your calculator and round to 1 decimal place unless told otherwise.

1.Find the area of a semicircle with a radius of 8 cm, correct to 1 decimal place.

Answer: 100.5 cm2

  1. A = ½ × π × r2 = ½ × π × 64
  2. ≈ 100.5 cm2
2.A circle has a diameter of 6 cm. Find its area, correct to 1 decimal place.

Answer: 28.3 cm2

  1. r = 6 ÷ 2 = 3 cm
  2. A = π × r2 = π × 32 = π × 9
  3. ≈ 28.3 cm2
3.Find the area of a semicircle with a radius of 16 cm, correct to 1 decimal place.

Answer: 402.1 cm2

  1. A = ½ × π × r2 = ½ × π × 256
  2. ≈ 402.1 cm2
4.A circle has a radius of 15 cm. Find its area, correct to 1 decimal place.

Answer: 706.9 cm2

  1. A = π × r2 = π × 152 = π × 225
  2. ≈ 706.9 cm2
5.A circle has a circumference of 4π cm. Find its radius and its area (leave the area in terms of π).

Answer: r = 2 cm; A = 4π cm2

  1. C = 2πr, so 2πr = 4π
  2. r = 2 cm
  3. A = πr2 = 4π cm2
6.A circle has a circumference of 8π cm. Find its radius and its area (leave the area in terms of π).

Answer: r = 4 cm; A = 16π cm2

  1. C = 2πr, so 2πr = 8π
  2. r = 4 cm
  3. A = πr2 = 16π cm2
7.Find the area of a semicircle with a radius of 13 cm, correct to 1 decimal place.

Answer: 265.5 cm2

  1. A = ½ × π × r2 = ½ × π × 169
  2. ≈ 265.5 cm2
8.A circle has a diameter of 30 cm. Find its area, correct to 1 decimal place.

Answer: 706.9 cm2

  1. r = 30 ÷ 2 = 15 cm
  2. A = π × r2 = π × 152 = π × 225
  3. ≈ 706.9 cm2
9.A circle has a radius of 4 cm. Find its area, correct to 1 decimal place.

Answer: 50.3 cm2

  1. A = π × r2 = π × 42 = π × 16
  2. ≈ 50.3 cm2
10.Find the area of a semicircle with a radius of 5 cm, correct to 1 decimal place.

Answer: 39.3 cm2

  1. A = ½ × π × r2 = ½ × π × 25
  2. ≈ 39.3 cm2
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