Year 10 Simple and Compound Interest Worksheet — Level 2 — Practice Set 2 — Answers
Answer sheet with worked solutions for the Year 10 financial mathematics worksheet.
Year 10 Simple and Compound Interest Worksheet — Level 2 — Practice Set 2 — Answers
Show your working. Write the rate as a decimal (5% = 0.05). Round money to the nearest cent.
1.$3,250.00 is invested at 3% per year, compounded yearly, for 6 years. Find the final amount and the interest earned, to the nearest cent.
Answer: Amount $3,880.67; interest $630.67
- A = P(1 + r)n = $3,250.00 × (1 + 0.03)6
- = $3,250.00 × 1.194052
- ≈ $3,880.67
- Interest = $3,880.67 − $3,250.00 = $630.67
2.Find the simple interest on $12,500.00 invested at 4.5% per year for 6 years. What is the total value at the end?
Answer: Interest $3,375.00; total $15,875.00
- I = P × r × n = $12,500.00 × 0.045 × 6
- = $3,375.00
- Total = $12,500.00 + $3,375.00 = $15,875.00
3.Find the simple interest on $4,750.00 invested at 3% per year for 5 years. What is the total value at the end?
Answer: Interest $712.50; total $5,462.50
- I = P × r × n = $4,750.00 × 0.03 × 5
- = $712.50
- Total = $4,750.00 + $712.50 = $5,462.50
4.$9,000.00 is invested at 4% per year, compounded yearly, for 6 years. Find the final amount and the interest earned, to the nearest cent.
Answer: Amount $11,387.87; interest $2,387.87
- A = P(1 + r)n = $9,000.00 × (1 + 0.04)6
- = $9,000.00 × 1.265319
- ≈ $11,387.87
- Interest = $11,387.87 − $9,000.00 = $2,387.87
5.$1,750.00 is invested at 6% per year, compounded yearly, for 6 years. Find the final amount and the interest earned, to the nearest cent.
Answer: Amount $2,482.41; interest $732.41
- A = P(1 + r)n = $1,750.00 × (1 + 0.06)6
- = $1,750.00 × 1.418519
- ≈ $2,482.41
- Interest = $2,482.41 − $1,750.00 = $732.41
6.Find the simple interest on $1,250.00 invested at 5% per year for 6 years. What is the total value at the end?
Answer: Interest $375.00; total $1,625.00
- I = P × r × n = $1,250.00 × 0.05 × 6
- = $375.00
- Total = $1,250.00 + $375.00 = $1,625.00
7.$2,000.00 is invested at 3% per year, compounded yearly, for 2 years. Find the final amount and the interest earned, to the nearest cent.
Answer: Amount $2,121.80; interest $121.80
- A = P(1 + r)n = $2,000.00 × (1 + 0.03)2
- = $2,000.00 × 1.0609
- ≈ $2,121.80
- Interest = $2,121.80 − $2,000.00 = $121.80
8.$15,000.00 is invested at 2.5% per year, compounded yearly, for 6 years. Find the final amount and the interest earned, to the nearest cent.
Answer: Amount $17,395.40; interest $2,395.40
- A = P(1 + r)n = $15,000.00 × (1 + 0.025)6
- = $15,000.00 × 1.159693
- ≈ $17,395.40
- Interest = $17,395.40 − $15,000.00 = $2,395.40
Marking tips
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