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Year 10 Gradient and Linear Equations Worksheet — Level 1 — Practice Set 4 — Answers

Answer sheet with worked solutions for the Year 10 linear relationships & graphs worksheet.

Success TutoringWorksheetsAnswer sheetYear 10 · Mathematics · Linear Relationships & Graphs

Year 10 Gradient and Linear Equations Worksheet — Level 1 — Practice Set 4 — Answers

Show your working. Gradient = rise ÷ run; the equation of a line can be written as y = (gradient)x + (y-intercept).

1.For the line y = −2x + 2, write the gradient and the y-intercept.

Answer: gradient −2; y-intercept 2

In y = (gradient)x + (y-intercept), the number multiplying x is the gradient and the constant is where the line crosses the y-axis.

2.For the line y = x − 3, write the gradient and the y-intercept.

Answer: gradient 1; y-intercept −3

In y = (gradient)x + (y-intercept), the number multiplying x is the gradient and the constant is where the line crosses the y-axis.

3.For the line y = x − 1, write the gradient and the y-intercept.

Answer: gradient 1; y-intercept −1

In y = (gradient)x + (y-intercept), the number multiplying x is the gradient and the constant is where the line crosses the y-axis.

4.For the line y = x + 4, write the gradient and the y-intercept.

Answer: gradient 1; y-intercept 4

In y = (gradient)x + (y-intercept), the number multiplying x is the gradient and the constant is where the line crosses the y-axis.

5.Find the gradient of the line through (0, 3) and (1, 4).

Answer: 1

  1. gradient = rise ÷ run = (4 − 3) ÷ (1 − 0)
  2. = 1 ÷ 1 = 1
6.For the line y = 4x − 7, write the gradient and the y-intercept.

Answer: gradient 4; y-intercept −7

In y = (gradient)x + (y-intercept), the number multiplying x is the gradient and the constant is where the line crosses the y-axis.

7.Find the gradient of the line through (−5, 0) and (−6, −1).

Answer: 1

  1. gradient = rise ÷ run = (−1 − 0) ÷ (−6 − (−5))
  2. = −1 ÷ −1 = 1
8.For the line y = 3x + 5, write the gradient and the y-intercept.

Answer: gradient 3; y-intercept 5

In y = (gradient)x + (y-intercept), the number multiplying x is the gradient and the constant is where the line crosses the y-axis.

9.Find the gradient of the line through (−2, 2) and (3, 12).

Answer: 2

  1. gradient = rise ÷ run = (12 − 2) ÷ (3 − (−2))
  2. = 10 ÷ 5 = 2
10.For the line y = −2x + 5, write the gradient and the y-intercept.

Answer: gradient −2; y-intercept 5

In y = (gradient)x + (y-intercept), the number multiplying x is the gradient and the constant is where the line crosses the y-axis.

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