Year 10 Trigonometry (Finding Sides) Worksheet — Level 1 — Answers
Answer sheet with worked solutions for the Year 10 trigonometry worksheet.
Year 10 · Mathematics · Trigonometry
Year 10 Trigonometry (Finding Sides) Worksheet — Level 1 — Answers
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Label the sides (opposite, adjacent, hypotenuse), choose the ratio (SOH CAH TOA), then solve.
1.In a right-angled triangle, the hypotenuse is 26 cm and one angle is 35°. Find the side opposite the 35° angle, to 1 decimal place.
Answer: 14.9 cm
- sin 35° = opposite ÷ hypotenuse
- opposite = 26 × sin 35°
- ≈ 14.9
2.In a right-angled triangle, the hypotenuse is 21 cm and one angle is 29°. Find the side opposite the 29° angle, to 1 decimal place.
Answer: 10.2 cm
- sin 29° = opposite ÷ hypotenuse
- opposite = 21 × sin 29°
- ≈ 10.2
3.In a right-angled triangle, the hypotenuse is 27 cm and one angle is 20°. Find the side opposite the 20° angle, to 1 decimal place.
Answer: 9.2 cm
- sin 20° = opposite ÷ hypotenuse
- opposite = 27 × sin 20°
- ≈ 9.2
4.In a right-angled triangle, the hypotenuse is 18 cm and one angle is 56°. Find the side opposite the 56° angle, to 1 decimal place.
Answer: 14.9 cm
- sin 56° = opposite ÷ hypotenuse
- opposite = 18 × sin 56°
- ≈ 14.9
5.In a right-angled triangle, the hypotenuse is 20 cm and one angle is 21°. Find the side opposite the 21° angle, to 1 decimal place.
Answer: 7.2 cm
- sin 21° = opposite ÷ hypotenuse
- opposite = 20 × sin 21°
- ≈ 7.2
6.In a right-angled triangle, the hypotenuse is 15 cm and one angle is 65°. Find the side opposite the 65° angle, to 1 decimal place.
Answer: 13.6 cm
- sin 65° = opposite ÷ hypotenuse
- opposite = 15 × sin 65°
- ≈ 13.6
7.In a right-angled triangle, the hypotenuse is 25 cm and one angle is 52°. Find the side opposite the 52° angle, to 1 decimal place.
Answer: 19.7 cm
- sin 52° = opposite ÷ hypotenuse
- opposite = 25 × sin 52°
- ≈ 19.7
8.In a right-angled triangle, the hypotenuse is 19 cm and one angle is 52°. Find the side opposite the 52° angle, to 1 decimal place.
Answer: 15 cm
- sin 52° = opposite ÷ hypotenuse
- opposite = 19 × sin 52°
- ≈ 15
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