Year 10 Trigonometry (Finding Sides) Worksheet — Level 2 — Answers
Answer sheet with worked solutions for the Year 10 trigonometry worksheet.
Year 10 Trigonometry (Finding Sides) Worksheet — Level 2 — Answers
Label the sides (opposite, adjacent, hypotenuse), choose the ratio (SOH CAH TOA), then solve.
1.In a right-angled triangle, the hypotenuse is 12 cm and one angle is 37°. Find the side opposite the 37° angle, to 1 decimal place.
Answer: 7.2 cm
- sin 37° = opposite ÷ hypotenuse
- opposite = 12 × sin 37°
- ≈ 7.2
2.In a right-angled triangle, the side adjacent to a 54° angle is 25 m. Find the opposite side, to 1 decimal place.
Answer: 34.4 m
- tan 54° = opposite ÷ adjacent
- opposite = 25 × tan 54°
- ≈ 34.4
3.In a right-angled triangle, the hypotenuse is 11 cm and one angle is 42°. Find the side adjacent to the 42° angle, to 1 decimal place.
Answer: 8.2 cm
- cos 42° = adjacent ÷ hypotenuse
- adjacent = 11 × cos 42°
- ≈ 8.2
4.In a right-angled triangle, the hypotenuse is 17 cm and one angle is 61°. Find the side adjacent to the 61° angle, to 1 decimal place.
Answer: 8.2 cm
- cos 61° = adjacent ÷ hypotenuse
- adjacent = 17 × cos 61°
- ≈ 8.2
5.In a right-angled triangle, the hypotenuse is 24 cm and one angle is 51°. Find the side adjacent to the 51° angle, to 1 decimal place.
Answer: 15.1 cm
- cos 51° = adjacent ÷ hypotenuse
- adjacent = 24 × cos 51°
- ≈ 15.1
6.In a right-angled triangle, the hypotenuse is 29 cm and one angle is 32°. Find the side adjacent to the 32° angle, to 1 decimal place.
Answer: 24.6 cm
- cos 32° = adjacent ÷ hypotenuse
- adjacent = 29 × cos 32°
- ≈ 24.6
7.In a right-angled triangle, the side adjacent to a 62° angle is 11 m. Find the opposite side, to 1 decimal place.
Answer: 20.7 m
- tan 62° = opposite ÷ adjacent
- opposite = 11 × tan 62°
- ≈ 20.7
8.In a right-angled triangle, the side adjacent to a 24° angle is 25 m. Find the opposite side, to 1 decimal place.
Answer: 11.1 m
- tan 24° = opposite ÷ adjacent
- opposite = 25 × tan 24°
- ≈ 11.1
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