Year 10 Trigonometry (Finding Sides) Worksheet — Level 2 — Practice Set 2 — Answers
Answer sheet with worked solutions for the Year 10 trigonometry worksheet.
Year 10 Trigonometry (Finding Sides) Worksheet — Level 2 — Practice Set 2 — Answers
Label the sides (opposite, adjacent, hypotenuse), choose the ratio (SOH CAH TOA), then solve.
1.In a right-angled triangle, the side adjacent to a 20° angle is 19 m. Find the opposite side, to 1 decimal place.
Answer: 6.9 m
- tan 20° = opposite ÷ adjacent
- opposite = 19 × tan 20°
- ≈ 6.9
2.In a right-angled triangle, the hypotenuse is 24 cm and one angle is 26°. Find the side adjacent to the 26° angle, to 1 decimal place.
Answer: 21.6 cm
- cos 26° = adjacent ÷ hypotenuse
- adjacent = 24 × cos 26°
- ≈ 21.6
3.In a right-angled triangle, the hypotenuse is 5 cm and one angle is 51°. Find the side adjacent to the 51° angle, to 1 decimal place.
Answer: 3.1 cm
- cos 51° = adjacent ÷ hypotenuse
- adjacent = 5 × cos 51°
- ≈ 3.1
4.In a right-angled triangle, the hypotenuse is 23 cm and one angle is 50°. Find the side opposite the 50° angle, to 1 decimal place.
Answer: 17.6 cm
- sin 50° = opposite ÷ hypotenuse
- opposite = 23 × sin 50°
- ≈ 17.6
5.In a right-angled triangle, the hypotenuse is 10 cm and one angle is 51°. Find the side opposite the 51° angle, to 1 decimal place.
Answer: 7.8 cm
- sin 51° = opposite ÷ hypotenuse
- opposite = 10 × sin 51°
- ≈ 7.8
6.In a right-angled triangle, the side adjacent to a 59° angle is 5 m. Find the opposite side, to 1 decimal place.
Answer: 8.3 m
- tan 59° = opposite ÷ adjacent
- opposite = 5 × tan 59°
- ≈ 8.3
7.In a right-angled triangle, the side adjacent to a 61° angle is 23 m. Find the opposite side, to 1 decimal place.
Answer: 41.5 m
- tan 61° = opposite ÷ adjacent
- opposite = 23 × tan 61°
- ≈ 41.5
8.In a right-angled triangle, the hypotenuse is 5 cm and one angle is 57°. Find the side adjacent to the 57° angle, to 1 decimal place.
Answer: 2.7 cm
- cos 57° = adjacent ÷ hypotenuse
- adjacent = 5 × cos 57°
- ≈ 2.7
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