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Year 11 Simple and Compound Interest Worksheet — Level 1 — Practice Set 3 — Answers

Answer sheet with worked solutions for the Year 11 financial mathematics worksheet.

Success TutoringWorksheetsAnswer sheetYear 11 · Mathematics · Financial Mathematics

Year 11 Simple and Compound Interest Worksheet — Level 1 — Practice Set 3 — Answers

Show your working. Write the rate as a decimal (5% = 0.05). Round money to the nearest cent.

1.Find the simple interest on $8,000.00 invested at 4% per year for 2 years. What is the total value at the end?

Answer: Interest $640.00; total $8,640.00

  1. I = P × r × n = $8,000.00 × 0.04 × 2
  2. = $640.00
  3. Total = $8,000.00 + $640.00 = $8,640.00
2.Find the simple interest on $11,000.00 invested at 4.5% per year for 2 years. What is the total value at the end?

Answer: Interest $990.00; total $11,990.00

  1. I = P × r × n = $11,000.00 × 0.045 × 2
  2. = $990.00
  3. Total = $11,000.00 + $990.00 = $11,990.00
3.Find the simple interest on $3,750.00 invested at 2.5% per year for 6 years. What is the total value at the end?

Answer: Interest $562.50; total $4,312.50

  1. I = P × r × n = $3,750.00 × 0.025 × 6
  2. = $562.50
  3. Total = $3,750.00 + $562.50 = $4,312.50
4.Find the simple interest on $7,000.00 invested at 3% per year for 5 years. What is the total value at the end?

Answer: Interest $1,050.00; total $8,050.00

  1. I = P × r × n = $7,000.00 × 0.03 × 5
  2. = $1,050.00
  3. Total = $7,000.00 + $1,050.00 = $8,050.00
5.Find the simple interest on $10,250.00 invested at 4% per year for 5 years. What is the total value at the end?

Answer: Interest $2,050.00; total $12,300.00

  1. I = P × r × n = $10,250.00 × 0.04 × 5
  2. = $2,050.00
  3. Total = $10,250.00 + $2,050.00 = $12,300.00
6.Find the simple interest on $6,500.00 invested at 3% per year for 6 years. What is the total value at the end?

Answer: Interest $1,170.00; total $7,670.00

  1. I = P × r × n = $6,500.00 × 0.03 × 6
  2. = $1,170.00
  3. Total = $6,500.00 + $1,170.00 = $7,670.00
7.Find the simple interest on $1,000.00 invested at 6% per year for 2 years. What is the total value at the end?

Answer: Interest $120.00; total $1,120.00

  1. I = P × r × n = $1,000.00 × 0.06 × 2
  2. = $120.00
  3. Total = $1,000.00 + $120.00 = $1,120.00
8.Find the simple interest on $14,500.00 invested at 2.5% per year for 6 years. What is the total value at the end?

Answer: Interest $2,175.00; total $16,675.00

  1. I = P × r × n = $14,500.00 × 0.025 × 6
  2. = $2,175.00
  3. Total = $14,500.00 + $2,175.00 = $16,675.00
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