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Year 11 Coordinates: Quadrants, Midpoints and Distance Worksheet — Level 3 — Practice Set 2 — Answers

Answer sheet with worked solutions for the Year 11 geometry worksheet.

Success TutoringWorksheetsAnswer sheetYear 11 · Mathematics · Geometry

Year 11 Coordinates: Quadrants, Midpoints and Distance Worksheet — Level 3 — Practice Set 2 — Answers

Midpoint = (average of the x-values, average of the y-values). Distance: use Pythagoras with the horizontal and vertical changes.

1.Find the midpoint of the segment joining (2, −3) and (−1, 4).

Answer: (0.5, 0.5)

  1. x: (2 + (−1)) ÷ 2 = 0.5
  2. y: (−3 + 4) ÷ 2 = 0.5
2.Find the distance between (−4, −1) and (−10, 7).

Answer: 10

  1. Horizontal change = 6, vertical change = 8
  2. d = √(62 + 82) = √100
  3. = 10
3.Find the midpoint of the segment joining (9, −5) and (−8, 9).

Answer: (0.5, 2)

  1. x: (9 + (−8)) ÷ 2 = 0.5
  2. y: (−5 + 9) ÷ 2 = 2
4.Find the distance between (−3, −3) and (2, −15).

Answer: 13

  1. Horizontal change = 5, vertical change = 12
  2. d = √(52 + 122) = √169
  3. = 13
5.Find the midpoint of the segment joining (3, 8) and (5, −2).

Answer: (4, 3)

  1. x: (3 + 5) ÷ 2 = 4
  2. y: (8 + (−2)) ÷ 2 = 3
6.Find the distance between (−1, 3) and (2, 7).

Answer: 5

  1. Horizontal change = 3, vertical change = 4
  2. d = √(32 + 42) = √25
  3. = 5
7.Find the midpoint of the segment joining (−9, −7) and (−6, 9).

Answer: (−7.5, 1)

  1. x: (−9 + (−6)) ÷ 2 = −7.5
  2. y: (−7 + 9) ÷ 2 = 1
8.Find the distance between (−1, −1) and (2, 3).

Answer: 5

  1. Horizontal change = 3, vertical change = 4
  2. d = √(32 + 42) = √25
  3. = 5
9.Find the distance between (−5, −2) and (−8, −6).

Answer: 5

  1. Horizontal change = 3, vertical change = 4
  2. d = √(32 + 42) = √25
  3. = 5
10.Find the distance between (−2, 2) and (6, 17).

Answer: 17

  1. Horizontal change = 8, vertical change = 15
  2. d = √(82 + 152) = √289
  3. = 17
11.Find the midpoint of the segment joining (0, 9) and (−1, 8).

Answer: (−0.5, 8.5)

  1. x: (0 + (−1)) ÷ 2 = −0.5
  2. y: (9 + 8) ÷ 2 = 8.5
12.Find the distance between (3, −1) and (12, 11).

Answer: 15

  1. Horizontal change = 9, vertical change = 12
  2. d = √(92 + 122) = √225
  3. = 15
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