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Year 11 Gradient and Linear Equations Worksheet — Level 3 — Answers

Answer sheet with worked solutions for the Year 11 linear relationships & graphs worksheet.

Success TutoringWorksheetsAnswer sheetYear 11 · Mathematics · Linear Relationships & Graphs

Year 11 Gradient and Linear Equations Worksheet — Level 3 — Answers

Show your working. Gradient = rise ÷ run; the equation of a line can be written as y = (gradient)x + (y-intercept).

1.For the line y = −x + 1, write the gradient and the y-intercept.

Answer: gradient −1; y-intercept 1

In y = (gradient)x + (y-intercept), the number multiplying x is the gradient and the constant is where the line crosses the y-axis.

2.For the line y = −3x − 9, write the gradient and the y-intercept.

Answer: gradient −3; y-intercept −9

In y = (gradient)x + (y-intercept), the number multiplying x is the gradient and the constant is where the line crosses the y-axis.

3.A line has a gradient of 3 and passes through (0, 4). Find its equation.

Answer: y = 3x + 4

  1. y = 3x + (y-intercept)
  2. 4 = 3 × 0 + (y-intercept)
  3. y-intercept = 4 − 0 = 4
  4. y = 3x + 4
4.For the line y = 3x + 8, write the gradient and the y-intercept.

Answer: gradient 3; y-intercept 8

In y = (gradient)x + (y-intercept), the number multiplying x is the gradient and the constant is where the line crosses the y-axis.

5.A line has a gradient of −3 and passes through (4, −15). Find its equation.

Answer: y = −3x − 3

  1. y = −3x + (y-intercept)
  2. −15 = −3 × 4 + (y-intercept)
  3. y-intercept = −15 − (−12) = −3
  4. y = −3x − 3
6.A line has a gradient of 1 and passes through (−2, 2). Find its equation.

Answer: y = x + 4

  1. y = 1x + (y-intercept)
  2. 2 = 1 × (−2) + (y-intercept)
  3. y-intercept = 2 − (−2) = 4
  4. y = x + 4
7.Does the point (−1, −8) lie on the line y = −x − 7?
  1. AYes
  2. BNo

Answer: No

Substitute x = −1: y = −1 × (−1) − 7 = −6, not −8.

8.A line has a gradient of 3 and passes through (4, 8). Find its equation.

Answer: y = 3x − 4

  1. y = 3x + (y-intercept)
  2. 8 = 3 × 4 + (y-intercept)
  3. y-intercept = 8 − 12 = −4
  4. y = 3x − 4
9.A line has a gradient of −3 and passes through (4, −4). Find its equation.

Answer: y = −3x + 8

  1. y = −3x + (y-intercept)
  2. −4 = −3 × 4 + (y-intercept)
  3. y-intercept = −4 − (−12) = 8
  4. y = −3x + 8
10.Does the point (0, 10) lie on the line y = 3x + 7?
  1. AYes
  2. BNo

Answer: No

Substitute x = 0: y = 3 × 0 + 7 = 7, not 10.

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