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Year 11 Gradient and Linear Equations Worksheet — Level 3 — Practice Set 4 — Answers

Answer sheet with worked solutions for the Year 11 linear relationships & graphs worksheet.

Success TutoringWorksheetsAnswer sheetYear 11 · Mathematics · Linear Relationships & Graphs

Year 11 Gradient and Linear Equations Worksheet — Level 3 — Practice Set 4 — Answers

Show your working. Gradient = rise ÷ run; the equation of a line can be written as y = (gradient)x + (y-intercept).

1.Does the point (2, −9) lie on the line y = −5x + 4?
  1. AYes
  2. BNo

Answer: No

Substitute x = 2: y = −5 × 2 + 4 = −6, not −9.

2.A line has a gradient of −4 and passes through (−3, 12). Find its equation.

Answer: y = −4x

  1. y = −4x + (y-intercept)
  2. 12 = −4 × (−3) + (y-intercept)
  3. y-intercept = 12 − 12 = 0
  4. y = −4x
3.Does the point (−5, −11) lie on the line y = x − 5?
  1. AYes
  2. BNo

Answer: No

Substitute x = −5: y = 1 × (−5) − 5 = −10, not −11.

4.For the line y = 3x + 4, write the gradient and the y-intercept.

Answer: gradient 3; y-intercept 4

In y = (gradient)x + (y-intercept), the number multiplying x is the gradient and the constant is where the line crosses the y-axis.

5.Does the point (−2, 3) lie on the line y = −5x − 7?
  1. AYes
  2. BNo

Answer: Yes

Substitute x = −2: y = −5 × (−2) − 7 = 3, which matches.

6.For the line y = x + 2, write the gradient and the y-intercept.

Answer: gradient 1; y-intercept 2

In y = (gradient)x + (y-intercept), the number multiplying x is the gradient and the constant is where the line crosses the y-axis.

7.Does the point (1, −7) lie on the line y = −3x − 7?
  1. AYes
  2. BNo

Answer: No

Substitute x = 1: y = −3 × 1 − 7 = −10, not −7.

8.A line has a gradient of 2 and passes through (−3, −5). Find its equation.

Answer: y = 2x + 1

  1. y = 2x + (y-intercept)
  2. −5 = 2 × (−3) + (y-intercept)
  3. y-intercept = −5 − (−6) = 1
  4. y = 2x + 1
9.A line has a gradient of −4 and passes through (1, 0). Find its equation.

Answer: y = −4x + 4

  1. y = −4x + (y-intercept)
  2. 0 = −4 × 1 + (y-intercept)
  3. y-intercept = 0 − (−4) = 4
  4. y = −4x + 4
10.For the line y = 2x − 3, write the gradient and the y-intercept.

Answer: gradient 2; y-intercept −3

In y = (gradient)x + (y-intercept), the number multiplying x is the gradient and the constant is where the line crosses the y-axis.

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