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Year 11 Gradient and Linear Equations Worksheet — Level 2 — Practice Set 2 — Answers

Answer sheet with worked solutions for the Year 11 linear relationships & graphs worksheet.

Success TutoringWorksheetsAnswer sheetYear 11 · Mathematics · Linear Relationships & Graphs

Year 11 Gradient and Linear Equations Worksheet — Level 2 — Practice Set 2 — Answers

Show your working. Gradient = rise ÷ run; the equation of a line can be written as y = (gradient)x + (y-intercept).

1.For the line y = −6x + 2, write the gradient and the y-intercept.

Answer: gradient −6; y-intercept 2

In y = (gradient)x + (y-intercept), the number multiplying x is the gradient and the constant is where the line crosses the y-axis.

2.For the line y = −x − 5, write the gradient and the y-intercept.

Answer: gradient −1; y-intercept −5

In y = (gradient)x + (y-intercept), the number multiplying x is the gradient and the constant is where the line crosses the y-axis.

3.For the line y = −2x − 7, write the gradient and the y-intercept.

Answer: gradient −2; y-intercept −7

In y = (gradient)x + (y-intercept), the number multiplying x is the gradient and the constant is where the line crosses the y-axis.

4.A line has a gradient of 3 and passes through (0, −5). Find its equation.

Answer: y = 3x − 5

  1. y = 3x + (y-intercept)
  2. −5 = 3 × 0 + (y-intercept)
  3. y-intercept = −5 − 0 = −5
  4. y = 3x − 5
5.Find the gradient of the line through (−3, −2) and (0, 1).

Answer: 1

  1. gradient = rise ÷ run = (1 − (−2)) ÷ (0 − (−3))
  2. = 3 ÷ 3 = 1
6.A line has a gradient of 3 and passes through (4, 11). Find its equation.

Answer: y = 3x − 1

  1. y = 3x + (y-intercept)
  2. 11 = 3 × 4 + (y-intercept)
  3. y-intercept = 11 − 12 = −1
  4. y = 3x − 1
7.For the line y = −x − 7, write the gradient and the y-intercept.

Answer: gradient −1; y-intercept −7

In y = (gradient)x + (y-intercept), the number multiplying x is the gradient and the constant is where the line crosses the y-axis.

8.Find the gradient of the line through (−4, −4) and (−7, −2).

Answer: −

  1. gradient = rise ÷ run = (−2 − (−4)) ÷ (−7 − (−4))
  2. = 2 ÷ −3 = −
9.For the line y = 4x + 1, write the gradient and the y-intercept.

Answer: gradient 4; y-intercept 1

In y = (gradient)x + (y-intercept), the number multiplying x is the gradient and the constant is where the line crosses the y-axis.

10.For the line y = −3x − 6, write the gradient and the y-intercept.

Answer: gradient −3; y-intercept −6

In y = (gradient)x + (y-intercept), the number multiplying x is the gradient and the constant is where the line crosses the y-axis.

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