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Year 11 Arithmetic and Geometric Sequences Worksheet — Level 2 — Practice Set 2 — Answers

Answer sheet with worked solutions for the Year 11 sequences & series worksheet.

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Year 11 Arithmetic and Geometric Sequences Worksheet — Level 2 — Practice Set 2 — Answers

Arithmetic: Tₙ = a + (n − 1)d. Geometric: Tₙ = arn − 1. Show your working.

1.Find the 13th term of the arithmetic sequence 19, 16, 13, 10, …

Answer: −17

  1. a = 19, d = −3
  2. T13 = 19 + 12 × −3 = −17
2.Find the sum of the first 21 terms of the arithmetic sequence −10, −9, −8, −7, …

Answer: 0

  1. Sₙ = n/2 × (2a + (n − 1)d)
  2. = 21/2 × (2 × −10 + 20 × 1)
  3. = 0
3.For the arithmetic sequence −7, −5, −3, −1, …, write the common difference and the rule for the nth term.

Answer: d = 2; Tₙ = 2n − 9

  1. d = −5 − (−7) = 2
  2. Tₙ = a + (n − 1)d = −7 + (n − 1) × 2 = 2n − 9
4.Find the sum of the first 5 terms of the geometric sequence −3, −9, −27, −81, …

Answer: −363

  1. Sₙ = a(rⁿ − 1) ÷ (r − 1)
  2. = −3 × (35 − 1) ÷ (3 − 1)
  3. = −363
5.Find the sum of the first 5 terms of the geometric sequence −1, −5, −25, −125, …

Answer: −781

  1. Sₙ = a(rⁿ − 1) ÷ (r − 1)
  2. = −1 × (55 − 1) ÷ (5 − 1)
  3. = −781
6.Find the sum of the first 7 terms of the geometric sequence −3, 6, −12, 24, …

Answer: −129

  1. Sₙ = a(rⁿ − 1) ÷ (r − 1)
  2. = −3 × ((−2)7 − 1) ÷ (−2 − 1)
  3. = −129
7.For the arithmetic sequence −2, −7, −12, −17, …, write the common difference and the rule for the nth term.

Answer: d = −5; Tₙ = −5n + 3

  1. d = −7 − (−2) = −5
  2. Tₙ = a + (n − 1)d = −2 + (n − 1) × −5 = −5n + 3
8.Find the 5th term of the geometric sequence 3, 15, 75, 375, …

Answer: 1875

  1. a = 3, r = 5
  2. T5 = 3 × 54 = 1875
9.For the arithmetic sequence 10, 12, 14, 16, …, write the common difference and the rule for the nth term.

Answer: d = 2; Tₙ = 2n + 8

  1. d = 12 − 10 = 2
  2. Tₙ = a + (n − 1)d = 10 + (n − 1) × 2 = 2n + 8
10.For the arithmetic sequence 6, 12, 18, 24, …, write the common difference and the rule for the nth term.

Answer: d = 6; Tₙ = 6n

  1. d = 12 − 6 = 6
  2. Tₙ = a + (n − 1)d = 6 + (n − 1) × 6 = 6n
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