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Year 13 Function Notation, Composites and Inverses Worksheet — Level 3 — Practice Set 3 — Answers

Answer sheet with worked solutions for the Year 13 functions worksheet.

Success TutoringWorksheetsAnswer sheetYear 13 · Mathematics · Functions

Year 13 Function Notation, Composites and Inverses Worksheet — Level 3 — Practice Set 3 — Answers

f(x) notation means "the value of the function at x". For a composite, substitute the inner function into the outer one. For an inverse, swap x and y and solve for y.

1.Find the inverse function of f(x) = 3x + 8.

Answer: f−1(x) =

  1. y = 3x + 8
  2. Swap x and y: x = 3y + 8
  3. Solve for y: y =
2.f(x) = 5x + 6 and g(x) = −x. Find g(f(x)) in simplest form.

Answer: −5x − 6

  1. g(f(x)) = −1(5x + 6)
  2. = −5x − 6
3.f(x) = −4x − 6 and g(x) = 4x − 5. Find f(g(x)) in simplest form.

Answer: −16x + 14

  1. f(g(x)) = −4(4x − 5) − 6
  2. = −16x + 14
4.f(x) = −4x − 3 and g(x) = 3x + 6. Find f(g(x)) in simplest form.

Answer: −12x − 27

  1. f(g(x)) = −4(3x + 6) − 3
  2. = −12x − 27
5.f(x) = x and g(x) = 5x − 2. Find g(f(x)) in simplest form.

Answer: 5x − 2

  1. g(f(x)) = 5(x) − 2
  2. = 5x − 2
6.f(x) = −x − 6 and g(x) = 3x + 6. Find g(f(x)) in simplest form.

Answer: −3x − 12

  1. g(f(x)) = 3(−x − 6) + 6
  2. = −3x − 12
7.Find the inverse function of f(x) = −5x − 1.

Answer: f−1(x) =

  1. y = −5x − 1
  2. Swap x and y: x = −5y − 1
  3. Solve for y: y =
8.f(x) = 2x + 5 and g(x) = 3x − 6. Find f(g(x)) in simplest form.

Answer: 6x − 7

  1. f(g(x)) = 2(3x − 6) + 5
  2. = 6x − 7
9.Find the inverse function of f(x) = 5x + 9.

Answer: f−1(x) =

  1. y = 5x + 9
  2. Swap x and y: x = 5y + 9
  3. Solve for y: y =
10.Find the inverse function of f(x) = −2x − 2.

Answer: f−1(x) =

  1. y = −2x − 2
  2. Swap x and y: x = −2y − 2
  3. Solve for y: y =
11.Find the inverse function of f(x) = x − 7.

Answer: f−1(x) = x + 7

  1. y = x − 7
  2. Swap x and y: x = y − 7
  3. Solve for y: y = x + 7
12.f(x) = −4x + 3 and g(x) = 3x − 4. Find g(f(x)) in simplest form.

Answer: −12x + 5

  1. g(f(x)) = 3(−4x + 3) − 4
  2. = −12x + 5
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