Bivariate Data: Correlation and Lines of Best Fit
A senior study guide to analysing two numerical variables: describing scatterplots, interpreting Pearson's r and the coefficient of…
- Difficulty
- Level 3 · Challenge
- Time
- 25 min
A senior maths worksheet on the binomial distribution: recognising Bernoulli trials and binomial situations, calculating P(X = k) with the binomial formula, cumulative and at least one probabilities, the mean np and variance np(1 − p), finding n and p from the mean and variance, and the smallest number of trials needed. Finishes with an extended seed germination problem. Full working is given for every answer.
Instant download · No sign-up · Free for personal, classroom and homeschool use
Curriculum: New Zealand Curriculum. We show specific outcome codes only where they have been verified against the official curriculum document.
Completed: The Binomial Distribution
Year 13 students (typically ages 17–18) working on statistics. It is pitched at level 3 · challenge.
Yes. The PDF includes a full answer sheet with the working for every question. You can also view the answers online.
About 50 minutes for 16 questions. Short, regular sessions work best: two or three a week beats one long one.
No. Click Download Free PDF and it opens immediately. It is free for personal, classroom and homeschool use.
Try Continuous Random Variables and Probability Density Functions.
Name
Date
Score /
Show your working. Give probabilities correct to 4 decimal places unless they are exact.
A Bernoulli trial has exactly two outcomes, success (probability p) and failure (probability 1 − p). For one trial, E(X) = p and Var(X) = p(1 − p).
X is binomial, written X ~ Bin(n, p), when it counts the successes in a fixed number n of independent Bernoulli trials, each with the same probability p of success.
Worked example. A basketball player makes 70% of free throws and takes 10 shots, independently. The number of shots made is X ~ Bin(10, 0.7). The number of shots taken until the first miss is not binomial, because n is not fixed.
If X ~ Bin(n, p), then P(X = k) = [sup n]C[sup k] p[sup k] (1 − p)[sup n − k] for k = 0, 1, 2, …, n. The nCk counts the orders in which k successes can occur among the n trials.
For at least one, use the complement: P(X ≥ 1) = 1 − P(X = 0) = 1 − (1 − p)n. For at most k, add P(X = 0) up to P(X = k).
Worked example. A fair coin is tossed 4 times. P(exactly 3 heads) = 4C3 (0.5)3 (0.5)1 = 4 × = 0.25, and P(at least one head) = 1 − (0.5)4 = 1 − 0.0625 = 0.9375.
If X ~ Bin(n, p), then E(X) = np, Var(X) = np(1 − p) and SD(X) = √(np(1 − p)). The mean is the long-run average number of successes in n trials.
Worked example. A fair die is rolled 30 times and X is the number of sixes. E(X) = 30 × = 5, Var(X) = 30 × × = ≈ 4.17 and SD ≈ 2.04.
Preview — the PDF contains the full resource and answer sheet.
A senior study guide to analysing two numerical variables: describing scatterplots, interpreting Pearson's r and the coefficient of…
A senior study guide to the bell curve: calculating z-scores, comparing results from different tests, using the 68–95–99.7 rule, reading…
A senior maths worksheet on continuous random variables: checking and completing probability density functions, finding probabilities by…
Free to print and share for personal, classroom and homeschool use. Please don't resell. Spotted an error? Let us know.