Year 7 Coordinates: Quadrants, Midpoints and Distance Worksheet — Level 3 — Answers
Answer sheet with worked solutions for the Year 7 geometry worksheet.
Year 7 Coordinates: Quadrants, Midpoints and Distance Worksheet — Level 3 — Answers
Midpoint = (average of the x-values, average of the y-values). Distance: use Pythagoras with the horizontal and vertical changes.
1.Find the midpoint of the segment joining (−2, −7) and (−9, 4).
Answer: (−5.5, −1.5)
- x: (−2 + (−9)) ÷ 2 = −5.5
- y: (−7 + 4) ÷ 2 = −1.5
2.Find the midpoint of the segment joining (7, 1) and (−8, 2).
Answer: (−0.5, 1.5)
- x: (7 + (−8)) ÷ 2 = −0.5
- y: (1 + 2) ÷ 2 = 1.5
3.Find the midpoint of the segment joining (−2, 2) and (−4, 8).
Answer: (−3, 5)
- x: (−2 + (−4)) ÷ 2 = −3
- y: (2 + 8) ÷ 2 = 5
4.Find the distance between (5, −3) and (4, −2), correct to 1 decimal place.
Answer: 1.4
- Horizontal change = 1, vertical change = 1
- d = √(12 + 12) = √2
- = 1.4
5.Find the distance between (0, 1) and (9, −11).
Answer: 15
- Horizontal change = 9, vertical change = 12
- d = √(92 + 122) = √225
- = 15
6.Find the distance between (3, 2) and (−6, 14).
Answer: 15
- Horizontal change = 9, vertical change = 12
- d = √(92 + 122) = √225
- = 15
7.Find the distance between (3, 0) and (8, −12).
Answer: 13
- Horizontal change = 5, vertical change = 12
- d = √(52 + 122) = √169
- = 13
8.Find the distance between (−3, 3) and (5, 18).
Answer: 17
- Horizontal change = 8, vertical change = 15
- d = √(82 + 152) = √289
- = 17
9.Find the distance between (−3, 2) and (0, 6).
Answer: 5
- Horizontal change = 3, vertical change = 4
- d = √(32 + 42) = √25
- = 5
10.Find the midpoint of the segment joining (−6, −7) and (3, 3).
Answer: (−1.5, −2)
- x: (−6 + 3) ÷ 2 = −1.5
- y: (−7 + 3) ÷ 2 = −2
11.Find the midpoint of the segment joining (9, 0) and (−8, −4).
Answer: (0.5, −2)
- x: (9 + (−8)) ÷ 2 = 0.5
- y: (0 + (−4)) ÷ 2 = −2
12.Find the midpoint of the segment joining (4, −7) and (−1, −1).
Answer: (1.5, −4)
- x: (4 + (−1)) ÷ 2 = 1.5
- y: (−7 + (−1)) ÷ 2 = −4
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