Year 9 Coordinates: Quadrants, Midpoints and Distance Worksheet — Level 3 — Practice Set 4 — Answers
Answer sheet with worked solutions for the Year 9 geometry worksheet.
Success TutoringWorksheetsAnswer sheetYear 9 · Mathematics · GeometryYear 9 Coordinates: Quadrants, Midpoints and Distance Worksheet — Level 3 — Practice Set 4 — Answers
Midpoint = (average of the x-values, average of the y-values). Distance: use Pythagoras with the horizontal and vertical changes.
1.Find the midpoint of the segment joining (4, 2) and (0, −8).
Answer: (2, −3)
- x: (4 + 0) ÷ 2 = 2
- y: (2 + (−8)) ÷ 2 = −3
2.Find the distance between (0, 1) and (−9, −11).
Answer: 15
- Horizontal change = 9, vertical change = 12
- d = √(92 + 122) = √225
- = 15
3.Find the distance between (1, −3) and (−7, 12).
Answer: 17
- Horizontal change = 8, vertical change = 15
- d = √(82 + 152) = √289
- = 17
4.Find the distance between (6, 3) and (9, −4), correct to 1 decimal place.
Answer: 7.6
- Horizontal change = 3, vertical change = 7
- d = √(32 + 72) = √58
- = 7.6
5.Find the distance between (−6, 1) and (−15, −3), correct to 1 decimal place.
Answer: 9.8
- Horizontal change = 9, vertical change = 4
- d = √(92 + 42) = √97
- = 9.8
6.Find the midpoint of the segment joining (4, 9) and (−5, 8).
Answer: (−0.5, 8.5)
- x: (4 + (−5)) ÷ 2 = −0.5
- y: (9 + 8) ÷ 2 = 8.5
7.Find the distance between (2, 4) and (11, −4), correct to 1 decimal place.
Answer: 12.0
- Horizontal change = 9, vertical change = 8
- d = √(92 + 82) = √145
- = 12.0
8.Find the midpoint of the segment joining (8, −5) and (6, −9).
Answer: (7, −7)
- x: (8 + 6) ÷ 2 = 7
- y: (−5 + (−9)) ÷ 2 = −7
9.Find the distance between (1, 6) and (2, −1), correct to 1 decimal place.
Answer: 7.1
- Horizontal change = 1, vertical change = 7
- d = √(12 + 72) = √50
- = 7.1
10.Find the midpoint of the segment joining (3, 2) and (7, 5).
Answer: (5, 3.5)
- x: (3 + 7) ÷ 2 = 5
- y: (2 + 5) ÷ 2 = 3.5
11.Find the distance between (−4, −2) and (−12, −17).
Answer: 17
- Horizontal change = 8, vertical change = 15
- d = √(82 + 152) = √289
- = 17
12.Find the distance between (−3, 2) and (3, 10).
Answer: 10
- Horizontal change = 6, vertical change = 8
- d = √(62 + 82) = √100
- = 10
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