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Year 10 Coordinates: Quadrants, Midpoints and Distance Worksheet — Level 3 — Practice Set 3 — Answers

Answer sheet with worked solutions for the Year 10 geometry worksheet.

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Success TutoringWorksheetsAnswer sheetYear 10 · Mathematics · Geometry

Year 10 Coordinates: Quadrants, Midpoints and Distance Worksheet — Level 3 — Practice Set 3 — Answers

Midpoint = (average of the x-values, average of the y-values). Distance: use Pythagoras with the horizontal and vertical changes.

1.Find the distance between (−5, 2) and (−12, 9), correct to 1 decimal place.

Answer: 9.9

  1. Horizontal change = 7, vertical change = 7
  2. d = √(72 + 72) = √98
  3. = 9.9
2.Find the midpoint of the segment joining (−4, 4) and (4, 5).

Answer: (0, 4.5)

  1. x: (−4 + 4) ÷ 2 = 0
  2. y: (4 + 5) ÷ 2 = 4.5
3.Find the distance between (1, 2) and (−8, 14).

Answer: 15

  1. Horizontal change = 9, vertical change = 12
  2. d = √(92 + 122) = √225
  3. = 15
4.Find the midpoint of the segment joining (−1, −1) and (−8, 9).

Answer: (−4.5, 4)

  1. x: (−1 + (−8)) ÷ 2 = −4.5
  2. y: (−1 + 9) ÷ 2 = 4
5.Find the midpoint of the segment joining (0, 6) and (2, 8).

Answer: (1, 7)

  1. x: (0 + 2) ÷ 2 = 1
  2. y: (6 + 8) ÷ 2 = 7
6.Find the midpoint of the segment joining (4, −7) and (8, −7).

Answer: (6, −7)

  1. x: (4 + 8) ÷ 2 = 6
  2. y: (−7 + (−7)) ÷ 2 = −7
7.Find the midpoint of the segment joining (2, −6) and (3, −9).

Answer: (2.5, −7.5)

  1. x: (2 + 3) ÷ 2 = 2.5
  2. y: (−6 + (−9)) ÷ 2 = −7.5
8.Find the midpoint of the segment joining (7, 1) and (−4, −7).

Answer: (1.5, −3)

  1. x: (7 + (−4)) ÷ 2 = 1.5
  2. y: (1 + (−7)) ÷ 2 = −3
9.Find the distance between (−5, 4) and (−2, −5), correct to 1 decimal place.

Answer: 9.5

  1. Horizontal change = 3, vertical change = 9
  2. d = √(32 + 92) = √90
  3. = 9.5
10.Find the midpoint of the segment joining (−1, 6) and (−2, 4).

Answer: (−1.5, 5)

  1. x: (−1 + (−2)) ÷ 2 = −1.5
  2. y: (6 + 4) ÷ 2 = 5
11.Find the distance between (−4, 4) and (4, 19).

Answer: 17

  1. Horizontal change = 8, vertical change = 15
  2. d = √(82 + 152) = √289
  3. = 17
12.Find the distance between (3, 4) and (−3, 12).

Answer: 10

  1. Horizontal change = 6, vertical change = 8
  2. d = √(62 + 82) = √100
  3. = 10
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