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Year 10 Gradient and Linear Equations Worksheet — Level 1 — Practice Set 2 — Answers

Answer sheet with worked solutions for the Year 10 linear relationships & graphs worksheet.

Success TutoringWorksheetsAnswer sheetYear 10 · Mathematics · Linear Relationships & Graphs

Year 10 Gradient and Linear Equations Worksheet — Level 1 — Practice Set 2 — Answers

Show your working. Gradient = rise ÷ run; the equation of a line can be written as y = (gradient)x + (y-intercept).

1.For the line y = −2x + 8, write the gradient and the y-intercept.

Answer: gradient −2; y-intercept 8

In y = (gradient)x + (y-intercept), the number multiplying x is the gradient and the constant is where the line crosses the y-axis.

2.For the line y = −3x − 7, write the gradient and the y-intercept.

Answer: gradient −3; y-intercept −7

In y = (gradient)x + (y-intercept), the number multiplying x is the gradient and the constant is where the line crosses the y-axis.

3.For the line y = 6x + 3, write the gradient and the y-intercept.

Answer: gradient 6; y-intercept 3

In y = (gradient)x + (y-intercept), the number multiplying x is the gradient and the constant is where the line crosses the y-axis.

4.Find the gradient of the line through (−6, −3) and (−5, −5).

Answer: −2

  1. gradient = rise ÷ run = (−5 − (−3)) ÷ (−5 − (−6))
  2. = −2 ÷ 1 = −2
5.Find the gradient of the line through (−4, 1) and (−5, 2).

Answer: −1

  1. gradient = rise ÷ run = (2 − 1) ÷ (−5 − (−4))
  2. = 1 ÷ −1 = −1
6.For the line y = −3x + 5, write the gradient and the y-intercept.

Answer: gradient −3; y-intercept 5

In y = (gradient)x + (y-intercept), the number multiplying x is the gradient and the constant is where the line crosses the y-axis.

7.For the line y = 2x + 5, write the gradient and the y-intercept.

Answer: gradient 2; y-intercept 5

In y = (gradient)x + (y-intercept), the number multiplying x is the gradient and the constant is where the line crosses the y-axis.

8.Find the gradient of the line through (3, 0) and (8, −5).

Answer: −1

  1. gradient = rise ÷ run = (−5 − 0) ÷ (8 − 3)
  2. = −5 ÷ 5 = −1
9.Find the gradient of the line through (−4, −4) and (0, 8).

Answer: 3

  1. gradient = rise ÷ run = (8 − (−4)) ÷ (0 − (−4))
  2. = 12 ÷ 4 = 3
10.For the line y = 2x + 6, write the gradient and the y-intercept.

Answer: gradient 2; y-intercept 6

In y = (gradient)x + (y-intercept), the number multiplying x is the gradient and the constant is where the line crosses the y-axis.

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