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Year 10 Gradient and Linear Equations Worksheet — Level 1 — Practice Set 3 — Answers

Answer sheet with worked solutions for the Year 10 linear relationships & graphs worksheet.

Success TutoringWorksheetsAnswer sheetYear 10 · Mathematics · Linear Relationships & Graphs

Year 10 Gradient and Linear Equations Worksheet — Level 1 — Practice Set 3 — Answers

Show your working. Gradient = rise ÷ run; the equation of a line can be written as y = (gradient)x + (y-intercept).

1.For the line y = x + 7, write the gradient and the y-intercept.

Answer: gradient 1; y-intercept 7

In y = (gradient)x + (y-intercept), the number multiplying x is the gradient and the constant is where the line crosses the y-axis.

2.For the line y = −6x + 1, write the gradient and the y-intercept.

Answer: gradient −6; y-intercept 1

In y = (gradient)x + (y-intercept), the number multiplying x is the gradient and the constant is where the line crosses the y-axis.

3.Find the gradient of the line through (4, 0) and (9, 5).

Answer: 1

  1. gradient = rise ÷ run = (5 − 0) ÷ (9 − 4)
  2. = 5 ÷ 5 = 1
4.Find the gradient of the line through (−4, 5) and (−7, −4).

Answer: 3

  1. gradient = rise ÷ run = (−4 − 5) ÷ (−7 − (−4))
  2. = −9 ÷ −3 = 3
5.Find the gradient of the line through (0, 2) and (−2, 8).

Answer: −3

  1. gradient = rise ÷ run = (8 − 2) ÷ (−2 − 0)
  2. = 6 ÷ −2 = −3
6.For the line y = −3x − 8, write the gradient and the y-intercept.

Answer: gradient −3; y-intercept −8

In y = (gradient)x + (y-intercept), the number multiplying x is the gradient and the constant is where the line crosses the y-axis.

7.For the line y = 3x + 2, write the gradient and the y-intercept.

Answer: gradient 3; y-intercept 2

In y = (gradient)x + (y-intercept), the number multiplying x is the gradient and the constant is where the line crosses the y-axis.

8.Find the gradient of the line through (4, −4) and (9, −14).

Answer: −2

  1. gradient = rise ÷ run = (−14 − (−4)) ÷ (9 − 4)
  2. = −10 ÷ 5 = −2
9.For the line y = −x − 6, write the gradient and the y-intercept.

Answer: gradient −1; y-intercept −6

In y = (gradient)x + (y-intercept), the number multiplying x is the gradient and the constant is where the line crosses the y-axis.

10.Find the gradient of the line through (6, 6) and (4, 12).

Answer: −3

  1. gradient = rise ÷ run = (12 − 6) ÷ (4 − 6)
  2. = 6 ÷ −2 = −3
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