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Year 10 Gradient and Linear Equations Worksheet — Level 2 — Practice Set 3 — Answers

Answer sheet with worked solutions for the Year 10 linear relationships & graphs worksheet.

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Year 10 Gradient and Linear Equations Worksheet — Level 2 — Practice Set 3 — Answers

Show your working. Gradient = rise ÷ run; the equation of a line can be written as y = (gradient)x + (y-intercept).

1.For the line y = 2x + 3, write the gradient and the y-intercept.

Answer: gradient 2; y-intercept 3

In y = (gradient)x + (y-intercept), the number multiplying x is the gradient and the constant is where the line crosses the y-axis.

2.A line has a gradient of −4 and passes through (−3, 11). Find its equation.

Answer: y = −4x − 1

  1. y = −4x + (y-intercept)
  2. 11 = −4 × (−3) + (y-intercept)
  3. y-intercept = 11 − 12 = −1
  4. y = −4x − 1
3.For the line y = 5x − 7, write the gradient and the y-intercept.

Answer: gradient 5; y-intercept −7

In y = (gradient)x + (y-intercept), the number multiplying x is the gradient and the constant is where the line crosses the y-axis.

4.A line has a gradient of 2 and passes through (0, 6). Find its equation.

Answer: y = 2x + 6

  1. y = 2x + (y-intercept)
  2. 6 = 2 × 0 + (y-intercept)
  3. y-intercept = 6 − 0 = 6
  4. y = 2x + 6
5.For the line y = 5x − 6, write the gradient and the y-intercept.

Answer: gradient 5; y-intercept −6

In y = (gradient)x + (y-intercept), the number multiplying x is the gradient and the constant is where the line crosses the y-axis.

6.Find the gradient of the line through (0, 4) and (−4, −3).

Answer:

  1. gradient = rise ÷ run = (−3 − 4) ÷ (−4 − 0)
  2. = −7 ÷ −4 =
7.Find the gradient of the line through (1, 6) and (−4, 1).

Answer: 1

  1. gradient = rise ÷ run = (1 − 6) ÷ (−4 − 1)
  2. = −5 ÷ −5 = 1
8.Find the gradient of the line through (−3, 5) and (2, 6).

Answer:

  1. gradient = rise ÷ run = (6 − 5) ÷ (2 − (−3))
  2. = 1 ÷ 5 =
9.Find the gradient of the line through (−5, −1) and (−2, 8).

Answer: 3

  1. gradient = rise ÷ run = (8 − (−1)) ÷ (−2 − (−5))
  2. = 9 ÷ 3 = 3
10.A line has a gradient of 2 and passes through (2, 13). Find its equation.

Answer: y = 2x + 9

  1. y = 2x + (y-intercept)
  2. 13 = 2 × 2 + (y-intercept)
  3. y-intercept = 13 − 4 = 9
  4. y = 2x + 9
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