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Year 11 Arithmetic and Geometric Sequences Worksheet — Level 1 — Practice Set 2 — Answers

Answer sheet with worked solutions for the Year 11 sequences & series worksheet.

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Year 11 Arithmetic and Geometric Sequences Worksheet — Level 1 — Practice Set 2 — Answers

Arithmetic: Tₙ = a + (n − 1)d. Geometric: Tₙ = arn − 1. Show your working.

1.For the arithmetic sequence 13, 22, 31, 40, …, write the common difference and the rule for the nth term.

Answer: d = 9; Tₙ = 9n + 4

  1. d = 22 − 13 = 9
  2. Tₙ = a + (n − 1)d = 13 + (n − 1) × 9 = 9n + 4
2.Find the 9th term of the arithmetic sequence 0, 4, 8, 12, …

Answer: 32

  1. a = 0, d = 4
  2. T9 = 0 + 8 × 4 = 32
3.Find the 11th term of the arithmetic sequence 18, 13, 8, 3, …

Answer: −32

  1. a = 18, d = −5
  2. T11 = 18 + 10 × −5 = −32
4.For the arithmetic sequence 15, 12, 9, 6, …, write the common difference and the rule for the nth term.

Answer: d = −3; Tₙ = −3n + 18

  1. d = 12 − 15 = −3
  2. Tₙ = a + (n − 1)d = 15 + (n − 1) × −3 = −3n + 18
5.Find the 28th term of the arithmetic sequence 15, 21, 27, 33, …

Answer: 177

  1. a = 15, d = 6
  2. T28 = 15 + 27 × 6 = 177
6.For the arithmetic sequence 1, −2, −5, −8, …, write the common difference and the rule for the nth term.

Answer: d = −3; Tₙ = −3n + 4

  1. d = −2 − 1 = −3
  2. Tₙ = a + (n − 1)d = 1 + (n − 1) × −3 = −3n + 4
7.For the arithmetic sequence 10, 8, 6, 4, …, write the common difference and the rule for the nth term.

Answer: d = −2; Tₙ = −2n + 12

  1. d = 8 − 10 = −2
  2. Tₙ = a + (n − 1)d = 10 + (n − 1) × −2 = −2n + 12
8.For the arithmetic sequence 16, 25, 34, 43, …, write the common difference and the rule for the nth term.

Answer: d = 9; Tₙ = 9n + 7

  1. d = 25 − 16 = 9
  2. Tₙ = a + (n − 1)d = 16 + (n − 1) × 9 = 9n + 7
9.For the arithmetic sequence 0, 7, 14, 21, …, write the common difference and the rule for the nth term.

Answer: d = 7; Tₙ = 7n − 7

  1. d = 7 − 0 = 7
  2. Tₙ = a + (n − 1)d = 0 + (n − 1) × 7 = 7n − 7
10.For the arithmetic sequence 15, 19, 23, 27, …, write the common difference and the rule for the nth term.

Answer: d = 4; Tₙ = 4n + 11

  1. d = 19 − 15 = 4
  2. Tₙ = a + (n − 1)d = 15 + (n − 1) × 4 = 4n + 11
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