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Year 11 Arithmetic and Geometric Sequences Worksheet — Level 1 — Practice Set 4 — Answers

Answer sheet with worked solutions for the Year 11 sequences & series worksheet.

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Year 11 Arithmetic and Geometric Sequences Worksheet — Level 1 — Practice Set 4 — Answers

Arithmetic: Tₙ = a + (n − 1)d. Geometric: Tₙ = arn − 1. Show your working.

1.For the arithmetic sequence 1, −2, −5, −8, …, write the common difference and the rule for the nth term.

Answer: d = −3; Tₙ = −3n + 4

  1. d = −2 − 1 = −3
  2. Tₙ = a + (n − 1)d = 1 + (n − 1) × −3 = −3n + 4
2.For the arithmetic sequence −1, 7, 15, 23, …, write the common difference and the rule for the nth term.

Answer: d = 8; Tₙ = 8n − 9

  1. d = 7 − (−1) = 8
  2. Tₙ = a + (n − 1)d = −1 + (n − 1) × 8 = 8n − 9
3.Find the 16th term of the arithmetic sequence 9, 8, 7, 6, …

Answer: −6

  1. a = 9, d = −1
  2. T16 = 9 + 15 × −1 = −6
4.Find the 12th term of the arithmetic sequence 1, −3, −7, −11, …

Answer: −43

  1. a = 1, d = −4
  2. T12 = 1 + 11 × −4 = −43
5.For the arithmetic sequence 20, 15, 10, 5, …, write the common difference and the rule for the nth term.

Answer: d = −5; Tₙ = −5n + 25

  1. d = 15 − 20 = −5
  2. Tₙ = a + (n − 1)d = 20 + (n − 1) × −5 = −5n + 25
6.For the arithmetic sequence −6, −7, −8, −9, …, write the common difference and the rule for the nth term.

Answer: d = −1; Tₙ = −n − 5

  1. d = −7 − (−6) = −1
  2. Tₙ = a + (n − 1)d = −6 + (n − 1) × −1 = −n − 5
7.Find the 8th term of the arithmetic sequence 17, 22, 27, 32, …

Answer: 52

  1. a = 17, d = 5
  2. T8 = 17 + 7 × 5 = 52
8.For the arithmetic sequence 17, 19, 21, 23, …, write the common difference and the rule for the nth term.

Answer: d = 2; Tₙ = 2n + 15

  1. d = 19 − 17 = 2
  2. Tₙ = a + (n − 1)d = 17 + (n − 1) × 2 = 2n + 15
9.For the arithmetic sequence 0, 4, 8, 12, …, write the common difference and the rule for the nth term.

Answer: d = 4; Tₙ = 4n − 4

  1. d = 4 − 0 = 4
  2. Tₙ = a + (n − 1)d = 0 + (n − 1) × 4 = 4n − 4
10.For the arithmetic sequence 12, 9, 6, 3, …, write the common difference and the rule for the nth term.

Answer: d = −3; Tₙ = −3n + 15

  1. d = 9 − 12 = −3
  2. Tₙ = a + (n − 1)d = 12 + (n − 1) × −3 = −3n + 15
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