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Year 6 Coordinates: Quadrants, Midpoints and Distance Worksheet — Level 3 — Answers

Answer sheet with worked solutions for the Year 6 geometry worksheet.

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Success TutoringWorksheetsAnswer sheetYear 6 · Mathematics · Geometry

Year 6 Coordinates: Quadrants, Midpoints and Distance Worksheet — Level 3 — Answers

Midpoint = (average of the x-values, average of the y-values). Distance: use Pythagoras with the horizontal and vertical changes.

1.Find the distance between (6, −4) and (15, 8).

Answer: 15

  1. Horizontal change = 9, vertical change = 12
  2. d = √(92 + 122) = √225
  3. = 15
2.Find the midpoint of the segment joining (3, 0) and (2, 0).

Answer: (2.5, 0)

  1. x: (3 + 2) ÷ 2 = 2.5
  2. y: (0 + 0) ÷ 2 = 0
3.Find the midpoint of the segment joining (−2, 6) and (6, −9).

Answer: (2, −1.5)

  1. x: (−2 + 6) ÷ 2 = 2
  2. y: (6 + (−9)) ÷ 2 = −1.5
4.Find the distance between (1, −3) and (8, −6), correct to 1 decimal place.

Answer: 7.6

  1. Horizontal change = 7, vertical change = 3
  2. d = √(72 + 32) = √58
  3. = 7.6
5.Find the distance between (4, −4) and (12, 11).

Answer: 17

  1. Horizontal change = 8, vertical change = 15
  2. d = √(82 + 152) = √289
  3. = 17
6.Find the distance between (6, 4) and (−2, 19).

Answer: 17

  1. Horizontal change = 8, vertical change = 15
  2. d = √(82 + 152) = √289
  3. = 17
7.Find the distance between (4, −2) and (−2, −10).

Answer: 10

  1. Horizontal change = 6, vertical change = 8
  2. d = √(62 + 82) = √100
  3. = 10
8.Find the midpoint of the segment joining (−1, −6) and (−4, 7).

Answer: (−2.5, 0.5)

  1. x: (−1 + (−4)) ÷ 2 = −2.5
  2. y: (−6 + 7) ÷ 2 = 0.5
9.Find the midpoint of the segment joining (−6, 3) and (−8, −1).

Answer: (−7, 1)

  1. x: (−6 + (−8)) ÷ 2 = −7
  2. y: (3 + (−1)) ÷ 2 = 1
10.Find the midpoint of the segment joining (4, −4) and (8, 2).

Answer: (6, −1)

  1. x: (4 + 8) ÷ 2 = 6
  2. y: (−4 + 2) ÷ 2 = −1
11.Find the distance between (−4, −2) and (−8, −7), correct to 1 decimal place.

Answer: 6.4

  1. Horizontal change = 4, vertical change = 5
  2. d = √(42 + 52) = √41
  3. = 6.4
12.Find the distance between (1, −1) and (−1, 8), correct to 1 decimal place.

Answer: 9.2

  1. Horizontal change = 2, vertical change = 9
  2. d = √(22 + 92) = √85
  3. = 9.2
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