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Year 6 Coordinates: Quadrants, Midpoints and Distance Worksheet — Level 3 — Practice Set 3 — Answers

Answer sheet with worked solutions for the Year 6 geometry worksheet.

Success TutoringWorksheetsAnswer sheetYear 6 · Mathematics · Geometry

Year 6 Coordinates: Quadrants, Midpoints and Distance Worksheet — Level 3 — Practice Set 3 — Answers

Midpoint = (average of the x-values, average of the y-values). Distance: use Pythagoras with the horizontal and vertical changes.

1.Find the distance between (0, 5) and (9, −7).

Answer: 15

  1. Horizontal change = 9, vertical change = 12
  2. d = √(92 + 122) = √225
  3. = 15
2.Find the midpoint of the segment joining (4, 0) and (3, −2).

Answer: (3.5, −1)

  1. x: (4 + 3) ÷ 2 = 3.5
  2. y: (0 + (−2)) ÷ 2 = −1
3.Find the distance between (3, 2) and (−6, −10).

Answer: 15

  1. Horizontal change = 9, vertical change = 12
  2. d = √(92 + 122) = √225
  3. = 15
4.Find the midpoint of the segment joining (−7, 8) and (5, 8).

Answer: (−1, 8)

  1. x: (−7 + 5) ÷ 2 = −1
  2. y: (8 + 8) ÷ 2 = 8
5.Find the distance between (5, −1) and (−3, 14).

Answer: 17

  1. Horizontal change = 8, vertical change = 15
  2. d = √(82 + 152) = √289
  3. = 17
6.Find the distance between (−3, −1) and (5, 5).

Answer: 10

  1. Horizontal change = 8, vertical change = 6
  2. d = √(82 + 62) = √100
  3. = 10
7.Find the midpoint of the segment joining (−7, −8) and (2, −3).

Answer: (−2.5, −5.5)

  1. x: (−7 + 2) ÷ 2 = −2.5
  2. y: (−8 + (−3)) ÷ 2 = −5.5
8.Find the midpoint of the segment joining (−2, 0) and (5, −1).

Answer: (1.5, −0.5)

  1. x: (−2 + 5) ÷ 2 = 1.5
  2. y: (0 + (−1)) ÷ 2 = −0.5
9.Find the midpoint of the segment joining (4, 1) and (5, 3).

Answer: (4.5, 2)

  1. x: (4 + 5) ÷ 2 = 4.5
  2. y: (1 + 3) ÷ 2 = 2
10.Find the midpoint of the segment joining (2, −3) and (8, 4).

Answer: (5, 0.5)

  1. x: (2 + 8) ÷ 2 = 5
  2. y: (−3 + 4) ÷ 2 = 0.5
11.Find the distance between (1, 5) and (−5, −3).

Answer: 10

  1. Horizontal change = 6, vertical change = 8
  2. d = √(62 + 82) = √100
  3. = 10
12.Find the distance between (1, −2) and (−4, 7), correct to 1 decimal place.

Answer: 10.3

  1. Horizontal change = 5, vertical change = 9
  2. d = √(52 + 92) = √106
  3. = 10.3
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