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Year 6 Coordinates: Quadrants, Midpoints and Distance Worksheet — Level 3 — Practice Set 4 — Answers

Answer sheet with worked solutions for the Year 6 geometry worksheet.

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Success TutoringWorksheetsAnswer sheetYear 6 · Mathematics · Geometry

Year 6 Coordinates: Quadrants, Midpoints and Distance Worksheet — Level 3 — Practice Set 4 — Answers

Midpoint = (average of the x-values, average of the y-values). Distance: use Pythagoras with the horizontal and vertical changes.

1.Find the distance between (6, 2) and (12, −6).

Answer: 10

  1. Horizontal change = 6, vertical change = 8
  2. d = √(62 + 82) = √100
  3. = 10
2.Find the distance between (3, 5) and (−2, 7), correct to 1 decimal place.

Answer: 5.4

  1. Horizontal change = 5, vertical change = 2
  2. d = √(52 + 22) = √29
  3. = 5.4
3.Find the midpoint of the segment joining (5, −2) and (−3, −4).

Answer: (1, −3)

  1. x: (5 + (−3)) ÷ 2 = 1
  2. y: (−2 + (−4)) ÷ 2 = −3
4.Find the midpoint of the segment joining (0, 8) and (4, −2).

Answer: (2, 3)

  1. x: (0 + 4) ÷ 2 = 2
  2. y: (8 + (−2)) ÷ 2 = 3
5.Find the midpoint of the segment joining (−1, 4) and (0, −9).

Answer: (−0.5, −2.5)

  1. x: (−1 + 0) ÷ 2 = −0.5
  2. y: (4 + (−9)) ÷ 2 = −2.5
6.Find the midpoint of the segment joining (−3, −3) and (−5, −4).

Answer: (−4, −3.5)

  1. x: (−3 + (−5)) ÷ 2 = −4
  2. y: (−3 + (−4)) ÷ 2 = −3.5
7.Find the midpoint of the segment joining (−9, 7) and (5, 5).

Answer: (−2, 6)

  1. x: (−9 + 5) ÷ 2 = −2
  2. y: (7 + 5) ÷ 2 = 6
8.Find the midpoint of the segment joining (−3, 9) and (5, 5).

Answer: (1, 7)

  1. x: (−3 + 5) ÷ 2 = 1
  2. y: (9 + 5) ÷ 2 = 7
9.Find the distance between (0, −5) and (5, −17).

Answer: 13

  1. Horizontal change = 5, vertical change = 12
  2. d = √(52 + 122) = √169
  3. = 13
10.Find the midpoint of the segment joining (−6, 9) and (9, 2).

Answer: (1.5, 5.5)

  1. x: (−6 + 9) ÷ 2 = 1.5
  2. y: (9 + 2) ÷ 2 = 5.5
11.Find the distance between (4, −2) and (9, 10).

Answer: 13

  1. Horizontal change = 5, vertical change = 12
  2. d = √(52 + 122) = √169
  3. = 13
12.Find the distance between (2, −6) and (−2, −8), correct to 1 decimal place.

Answer: 4.5

  1. Horizontal change = 4, vertical change = 2
  2. d = √(42 + 22) = √20
  3. = 4.5
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