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Year 7 Coordinates: Quadrants, Midpoints and Distance Worksheet — Level 3 — Practice Set 4 — Answers

Answer sheet with worked solutions for the Year 7 geometry worksheet.

Success TutoringWorksheetsAnswer sheetYear 7 · Mathematics · Geometry

Year 7 Coordinates: Quadrants, Midpoints and Distance Worksheet — Level 3 — Practice Set 4 — Answers

Midpoint = (average of the x-values, average of the y-values). Distance: use Pythagoras with the horizontal and vertical changes.

1.Find the midpoint of the segment joining (6, 5) and (4, 4).

Answer: (5, 4.5)

  1. x: (6 + 4) ÷ 2 = 5
  2. y: (5 + 4) ÷ 2 = 4.5
2.Find the distance between (2, −3) and (−1, −7).

Answer: 5

  1. Horizontal change = 3, vertical change = 4
  2. d = √(32 + 42) = √25
  3. = 5
3.Find the midpoint of the segment joining (−3, 9) and (5, 5).

Answer: (1, 7)

  1. x: (−3 + 5) ÷ 2 = 1
  2. y: (9 + 5) ÷ 2 = 7
4.Find the distance between (−2, 6) and (7, −6).

Answer: 15

  1. Horizontal change = 9, vertical change = 12
  2. d = √(92 + 122) = √225
  3. = 15
5.Find the distance between (0, −6) and (−8, −21).

Answer: 17

  1. Horizontal change = 8, vertical change = 15
  2. d = √(82 + 152) = √289
  3. = 17
6.Find the distance between (−6, −3) and (−11, 9).

Answer: 13

  1. Horizontal change = 5, vertical change = 12
  2. d = √(52 + 122) = √169
  3. = 13
7.Find the distance between (0, −5) and (−8, −20).

Answer: 17

  1. Horizontal change = 8, vertical change = 15
  2. d = √(82 + 152) = √289
  3. = 17
8.Find the midpoint of the segment joining (−6, −5) and (−9, −8).

Answer: (−7.5, −6.5)

  1. x: (−6 + (−9)) ÷ 2 = −7.5
  2. y: (−5 + (−8)) ÷ 2 = −6.5
9.Find the distance between (−5, 5) and (−3, −3), correct to 1 decimal place.

Answer: 8.2

  1. Horizontal change = 2, vertical change = 8
  2. d = √(22 + 82) = √68
  3. = 8.2
10.Find the distance between (3, −3) and (−6, −15).

Answer: 15

  1. Horizontal change = 9, vertical change = 12
  2. d = √(92 + 122) = √225
  3. = 15
11.Find the midpoint of the segment joining (−4, −5) and (−3, −5).

Answer: (−3.5, −5)

  1. x: (−4 + (−3)) ÷ 2 = −3.5
  2. y: (−5 + (−5)) ÷ 2 = −5
12.Find the distance between (4, −6) and (−5, 6).

Answer: 15

  1. Horizontal change = 9, vertical change = 12
  2. d = √(92 + 122) = √225
  3. = 15
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