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Year 8 Gradient and Linear Equations Worksheet — Level 1 — Practice Set 3 — Answers

Answer sheet with worked solutions for the Year 8 linear relationships & graphs worksheet.

Success TutoringWorksheetsAnswer sheetYear 8 · Mathematics · Linear Relationships & Graphs

Year 8 Gradient and Linear Equations Worksheet — Level 1 — Practice Set 3 — Answers

Show your working. Gradient = rise ÷ run; the equation of a line can be written as y = (gradient)x + (y-intercept).

1.For the line y = 5x + 6, write the gradient and the y-intercept.

Answer: gradient 5; y-intercept 6

In y = (gradient)x + (y-intercept), the number multiplying x is the gradient and the constant is where the line crosses the y-axis.

2.For the line y = −2x − 6, write the gradient and the y-intercept.

Answer: gradient −2; y-intercept −6

In y = (gradient)x + (y-intercept), the number multiplying x is the gradient and the constant is where the line crosses the y-axis.

3.Find the gradient of the line through (−1, −2) and (4, 8).

Answer: 2

  1. gradient = rise ÷ run = (8 − (−2)) ÷ (4 − (−1))
  2. = 10 ÷ 5 = 2
4.For the line y = 4x, write the gradient and the y-intercept.

Answer: gradient 4; y-intercept 0

In y = (gradient)x + (y-intercept), the number multiplying x is the gradient and the constant is where the line crosses the y-axis.

5.Find the gradient of the line through (3, 1) and (0, 4).

Answer: −1

  1. gradient = rise ÷ run = (4 − 1) ÷ (0 − 3)
  2. = 3 ÷ −3 = −1
6.For the line y = x + 5, write the gradient and the y-intercept.

Answer: gradient 1; y-intercept 5

In y = (gradient)x + (y-intercept), the number multiplying x is the gradient and the constant is where the line crosses the y-axis.

7.For the line y = −4x + 9, write the gradient and the y-intercept.

Answer: gradient −4; y-intercept 9

In y = (gradient)x + (y-intercept), the number multiplying x is the gradient and the constant is where the line crosses the y-axis.

8.For the line y = −x − 9, write the gradient and the y-intercept.

Answer: gradient −1; y-intercept −9

In y = (gradient)x + (y-intercept), the number multiplying x is the gradient and the constant is where the line crosses the y-axis.

9.For the line y = −x, write the gradient and the y-intercept.

Answer: gradient −1; y-intercept 0

In y = (gradient)x + (y-intercept), the number multiplying x is the gradient and the constant is where the line crosses the y-axis.

10.Find the gradient of the line through (3, −1) and (4, −3).

Answer: −2

  1. gradient = rise ÷ run = (−3 − (−1)) ÷ (4 − 3)
  2. = −2 ÷ 1 = −2
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