Year 9 Coordinates: Quadrants, Midpoints and Distance Worksheet — Level 3 — Practice Set 4 — Answers
Answer sheet with worked solutions for the Year 9 geometry worksheet.
Success TutoringWorksheetsAnswer sheetYear 9 · Mathematics · GeometryYear 9 Coordinates: Quadrants, Midpoints and Distance Worksheet — Level 3 — Practice Set 4 — Answers
Midpoint = (average of the x-values, average of the y-values). Distance: use Pythagoras with the horizontal and vertical changes.
1.Find the distance between (6, −4) and (12, −12).
Answer: 10
- Horizontal change = 6, vertical change = 8
- d = √(62 + 82) = √100
- = 10
2.Find the midpoint of the segment joining (8, 4) and (−5, −1).
Answer: (1.5, 1.5)
- x: (8 + (−5)) ÷ 2 = 1.5
- y: (4 + (−1)) ÷ 2 = 1.5
3.Find the distance between (4, 5) and (−4, −3), correct to 1 decimal place.
Answer: 11.3
- Horizontal change = 8, vertical change = 8
- d = √(82 + 82) = √128
- = 11.3
4.Find the distance between (−5, −6) and (−11, −14).
Answer: 10
- Horizontal change = 6, vertical change = 8
- d = √(62 + 82) = √100
- = 10
5.Find the distance between (2, 5) and (4, 1), correct to 1 decimal place.
Answer: 4.5
- Horizontal change = 2, vertical change = 4
- d = √(22 + 42) = √20
- = 4.5
6.Find the midpoint of the segment joining (9, −9) and (−2, 6).
Answer: (3.5, −1.5)
- x: (9 + (−2)) ÷ 2 = 3.5
- y: (−9 + 6) ÷ 2 = −1.5
7.Find the distance between (−2, 5) and (−5, 9).
Answer: 5
- Horizontal change = 3, vertical change = 4
- d = √(32 + 42) = √25
- = 5
8.Find the midpoint of the segment joining (8, −6) and (−9, 7).
Answer: (−0.5, 0.5)
- x: (8 + (−9)) ÷ 2 = −0.5
- y: (−6 + 7) ÷ 2 = 0.5
9.Find the distance between (−1, −4) and (0, −13), correct to 1 decimal place.
Answer: 9.1
- Horizontal change = 1, vertical change = 9
- d = √(12 + 92) = √82
- = 9.1
10.Find the midpoint of the segment joining (5, 0) and (−2, −3).
Answer: (1.5, −1.5)
- x: (5 + (−2)) ÷ 2 = 1.5
- y: (0 + (−3)) ÷ 2 = −1.5
11.Find the midpoint of the segment joining (−9, 2) and (−1, 9).
Answer: (−5, 5.5)
- x: (−9 + (−1)) ÷ 2 = −5
- y: (2 + 9) ÷ 2 = 5.5
12.Find the distance between (−1, −3) and (−4, −7).
Answer: 5
- Horizontal change = 3, vertical change = 4
- d = √(32 + 42) = √25
- = 5
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