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Year 9 Gradient and Linear Equations Worksheet — Level 3 — Practice Set 4 — Answers

Answer sheet with worked solutions for the Year 9 linear relationships & graphs worksheet.

Success TutoringWorksheetsAnswer sheetYear 9 · Mathematics · Linear Relationships & Graphs

Year 9 Gradient and Linear Equations Worksheet — Level 3 — Practice Set 4 — Answers

Show your working. Gradient = rise ÷ run; the equation of a line can be written as y = (gradient)x + (y-intercept).

1.A line has a gradient of 1 and passes through (4, 0). Find its equation.

Answer: y = x − 4

  1. y = 1x + (y-intercept)
  2. 0 = 1 × 4 + (y-intercept)
  3. y-intercept = 0 − 4 = −4
  4. y = x − 4
2.A line has a gradient of −1 and passes through (1, −6). Find its equation.

Answer: y = −x − 5

  1. y = −1x + (y-intercept)
  2. −6 = −1 × 1 + (y-intercept)
  3. y-intercept = −6 − (−1) = −5
  4. y = −x − 5
3.A line has a gradient of −2 and passes through (−4, 16). Find its equation.

Answer: y = −2x + 8

  1. y = −2x + (y-intercept)
  2. 16 = −2 × (−4) + (y-intercept)
  3. y-intercept = 16 − 8 = 8
  4. y = −2x + 8
4.A line has a gradient of 2 and passes through (3, 5). Find its equation.

Answer: y = 2x − 1

  1. y = 2x + (y-intercept)
  2. 5 = 2 × 3 + (y-intercept)
  3. y-intercept = 5 − 6 = −1
  4. y = 2x − 1
5.A line has a gradient of 3 and passes through (2, 4). Find its equation.

Answer: y = 3x − 2

  1. y = 3x + (y-intercept)
  2. 4 = 3 × 2 + (y-intercept)
  3. y-intercept = 4 − 6 = −2
  4. y = 3x − 2
6.For the line y = 6x + 2, write the gradient and the y-intercept.

Answer: gradient 6; y-intercept 2

In y = (gradient)x + (y-intercept), the number multiplying x is the gradient and the constant is where the line crosses the y-axis.

7.A line has a gradient of 5 and passes through (−4, −14). Find its equation.

Answer: y = 5x + 6

  1. y = 5x + (y-intercept)
  2. −14 = 5 × (−4) + (y-intercept)
  3. y-intercept = −14 − (−20) = 6
  4. y = 5x + 6
8.A line has a gradient of 4 and passes through (1, −1). Find its equation.

Answer: y = 4x − 5

  1. y = 4x + (y-intercept)
  2. −1 = 4 × 1 + (y-intercept)
  3. y-intercept = −1 − 4 = −5
  4. y = 4x − 5
9.For the line y = −3x − 1, write the gradient and the y-intercept.

Answer: gradient −3; y-intercept −1

In y = (gradient)x + (y-intercept), the number multiplying x is the gradient and the constant is where the line crosses the y-axis.

10.Does the point (4, −12) lie on the line y = −2x − 4?
  1. AYes
  2. BNo

Answer: Yes

Substitute x = 4: y = −2 × 4 − 4 = −12, which matches.

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