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Year 9 Gradient and Linear Equations Worksheet — Level 1 — Practice Set 2 — Answers

Answer sheet with worked solutions for the Year 9 linear relationships & graphs worksheet.

Success TutoringWorksheetsAnswer sheetYear 9 · Mathematics · Linear Relationships & Graphs

Year 9 Gradient and Linear Equations Worksheet — Level 1 — Practice Set 2 — Answers

Show your working. Gradient = rise ÷ run; the equation of a line can be written as y = (gradient)x + (y-intercept).

1.Find the gradient of the line through (−3, −1) and (−2, 0).

Answer: 1

  1. gradient = rise ÷ run = (0 − (−1)) ÷ (−2 − (−3))
  2. = 1 ÷ 1 = 1
2.For the line y = −6x + 9, write the gradient and the y-intercept.

Answer: gradient −6; y-intercept 9

In y = (gradient)x + (y-intercept), the number multiplying x is the gradient and the constant is where the line crosses the y-axis.

3.Find the gradient of the line through (−2, 5) and (3, 10).

Answer: 1

  1. gradient = rise ÷ run = (10 − 5) ÷ (3 − (−2))
  2. = 5 ÷ 5 = 1
4.For the line y = −5x, write the gradient and the y-intercept.

Answer: gradient −5; y-intercept 0

In y = (gradient)x + (y-intercept), the number multiplying x is the gradient and the constant is where the line crosses the y-axis.

5.Find the gradient of the line through (−2, −5) and (−6, 7).

Answer: −3

  1. gradient = rise ÷ run = (7 − (−5)) ÷ (−6 − (−2))
  2. = 12 ÷ −4 = −3
6.For the line y = x, write the gradient and the y-intercept.

Answer: gradient 1; y-intercept 0

In y = (gradient)x + (y-intercept), the number multiplying x is the gradient and the constant is where the line crosses the y-axis.

7.Find the gradient of the line through (4, 0) and (8, 4).

Answer: 1

  1. gradient = rise ÷ run = (4 − 0) ÷ (8 − 4)
  2. = 4 ÷ 4 = 1
8.Find the gradient of the line through (−3, 2) and (−5, −4).

Answer: 3

  1. gradient = rise ÷ run = (−4 − 2) ÷ (−5 − (−3))
  2. = −6 ÷ −2 = 3
9.Find the gradient of the line through (0, 6) and (−4, 14).

Answer: −2

  1. gradient = rise ÷ run = (14 − 6) ÷ (−4 − 0)
  2. = 8 ÷ −4 = −2
10.Find the gradient of the line through (0, 1) and (1, −2).

Answer: −3

  1. gradient = rise ÷ run = (−2 − 1) ÷ (1 − 0)
  2. = −3 ÷ 1 = −3
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