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Year 9 Gradient and Linear Equations Worksheet — Level 1 — Practice Set 3 — Answers

Answer sheet with worked solutions for the Year 9 linear relationships & graphs worksheet.

Success TutoringWorksheetsAnswer sheetYear 9 · Mathematics · Linear Relationships & Graphs

Year 9 Gradient and Linear Equations Worksheet — Level 1 — Practice Set 3 — Answers

Show your working. Gradient = rise ÷ run; the equation of a line can be written as y = (gradient)x + (y-intercept).

1.For the line y = −4x − 2, write the gradient and the y-intercept.

Answer: gradient −4; y-intercept −2

In y = (gradient)x + (y-intercept), the number multiplying x is the gradient and the constant is where the line crosses the y-axis.

2.Find the gradient of the line through (6, −6) and (3, 3).

Answer: −3

  1. gradient = rise ÷ run = (3 − (−6)) ÷ (3 − 6)
  2. = 9 ÷ −3 = −3
3.For the line y = 4x + 8, write the gradient and the y-intercept.

Answer: gradient 4; y-intercept 8

In y = (gradient)x + (y-intercept), the number multiplying x is the gradient and the constant is where the line crosses the y-axis.

4.For the line y = 2x + 7, write the gradient and the y-intercept.

Answer: gradient 2; y-intercept 7

In y = (gradient)x + (y-intercept), the number multiplying x is the gradient and the constant is where the line crosses the y-axis.

5.For the line y = 5x + 9, write the gradient and the y-intercept.

Answer: gradient 5; y-intercept 9

In y = (gradient)x + (y-intercept), the number multiplying x is the gradient and the constant is where the line crosses the y-axis.

6.Find the gradient of the line through (4, 0) and (3, −1).

Answer: 1

  1. gradient = rise ÷ run = (−1 − 0) ÷ (3 − 4)
  2. = −1 ÷ −1 = 1
7.Find the gradient of the line through (3, 0) and (6, −9).

Answer: −3

  1. gradient = rise ÷ run = (−9 − 0) ÷ (6 − 3)
  2. = −9 ÷ 3 = −3
8.Find the gradient of the line through (6, 0) and (10, 8).

Answer: 2

  1. gradient = rise ÷ run = (8 − 0) ÷ (10 − 6)
  2. = 8 ÷ 4 = 2
9.For the line y = −6x + 9, write the gradient and the y-intercept.

Answer: gradient −6; y-intercept 9

In y = (gradient)x + (y-intercept), the number multiplying x is the gradient and the constant is where the line crosses the y-axis.

10.Find the gradient of the line through (−6, 3) and (−11, 18).

Answer: −3

  1. gradient = rise ÷ run = (18 − 3) ÷ (−11 − (−6))
  2. = 15 ÷ −5 = −3
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