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Year 9 Gradient and Linear Equations Worksheet — Level 2 — Practice Set 4 — Answers

Answer sheet with worked solutions for the Year 9 linear relationships & graphs worksheet.

Success TutoringWorksheetsAnswer sheetYear 9 · Mathematics · Linear Relationships & Graphs

Year 9 Gradient and Linear Equations Worksheet — Level 2 — Practice Set 4 — Answers

Show your working. Gradient = rise ÷ run; the equation of a line can be written as y = (gradient)x + (y-intercept).

1.Find the gradient of the line through (2, 2) and (−1, −7).

Answer: 3

  1. gradient = rise ÷ run = (−7 − 2) ÷ (−1 − 2)
  2. = −9 ÷ −3 = 3
2.Find the gradient of the line through (−3, −1) and (0, −8).

Answer: −

  1. gradient = rise ÷ run = (−8 − (−1)) ÷ (0 − (−3))
  2. = −7 ÷ 3 = −
3.Find the gradient of the line through (−3, 5) and (1, 6).

Answer:

  1. gradient = rise ÷ run = (6 − 5) ÷ (1 − (−3))
  2. = 1 ÷ 4 =
4.A line has a gradient of 5 and passes through (0, 5). Find its equation.

Answer: y = 5x + 5

  1. y = 5x + (y-intercept)
  2. 5 = 5 × 0 + (y-intercept)
  3. y-intercept = 5 − 0 = 5
  4. y = 5x + 5
5.Find the gradient of the line through (2, −5) and (−2, −3).

Answer: −

  1. gradient = rise ÷ run = (−3 − (−5)) ÷ (−2 − 2)
  2. = 2 ÷ −4 = −
6.Find the gradient of the line through (6, 1) and (11, −6).

Answer: −

  1. gradient = rise ÷ run = (−6 − 1) ÷ (11 − 6)
  2. = −7 ÷ 5 = −
7.For the line y = 6x − 4, write the gradient and the y-intercept.

Answer: gradient 6; y-intercept −4

In y = (gradient)x + (y-intercept), the number multiplying x is the gradient and the constant is where the line crosses the y-axis.

8.For the line y = 2x + 8, write the gradient and the y-intercept.

Answer: gradient 2; y-intercept 8

In y = (gradient)x + (y-intercept), the number multiplying x is the gradient and the constant is where the line crosses the y-axis.

9.For the line y = 5x − 3, write the gradient and the y-intercept.

Answer: gradient 5; y-intercept −3

In y = (gradient)x + (y-intercept), the number multiplying x is the gradient and the constant is where the line crosses the y-axis.

10.A line has a gradient of −3 and passes through (4, −15). Find its equation.

Answer: y = −3x − 3

  1. y = −3x + (y-intercept)
  2. −15 = −3 × 4 + (y-intercept)
  3. y-intercept = −15 − (−12) = −3
  4. y = −3x − 3
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