10th Grade Simple and Compound Interest Worksheet — Level 2 — Answers
Answer sheet with worked solutions for the 10th Grade financial math worksheet.
10th Grade Simple and Compound Interest Worksheet — Level 2 — Answers
Show your work. Write the rate as a decimal (5% = 0.05). Round money to the nearest cent.
1.$6,500.00 is invested at 2% per year, compounded yearly, for 6 years. Find the final amount and the interest earned, to the nearest cent.
Answer: Amount $7,320.06; interest $820.06
- A = P(1 + r)n = $6,500.00 × (1 + 0.02)6
- = $6,500.00 × 1.126162
- ≈ $7,320.06
- Interest = $7,320.06 − $6,500.00 = $820.06
2.Find the simple interest on $2,750.00 invested at 4.5% per year for 2 years. What is the total value at the end?
Answer: Interest $247.50; total $2,997.50
- I = P × r × n = $2,750.00 × 0.045 × 2
- = $247.50
- Total = $2,750.00 + $247.50 = $2,997.50
3.Find the simple interest on $2,500.00 invested at 8% per year for 5 years. What is the total value at the end?
Answer: Interest $1,000.00; total $3,500.00
- I = P × r × n = $2,500.00 × 0.08 × 5
- = $1,000.00
- Total = $2,500.00 + $1,000.00 = $3,500.00
4.Find the simple interest on $5,000.00 invested at 2.5% per year for 5 years. What is the total value at the end?
Answer: Interest $625.00; total $5,625.00
- I = P × r × n = $5,000.00 × 0.025 × 5
- = $625.00
- Total = $5,000.00 + $625.00 = $5,625.00
5.Find the simple interest on $6,250.00 invested at 4.5% per year for 3 years. What is the total value at the end?
Answer: Interest $843.75; total $7,093.75
- I = P × r × n = $6,250.00 × 0.045 × 3
- = $843.75
- Total = $6,250.00 + $843.75 = $7,093.75
6.$1,750.00 is invested at 5% per year, compounded yearly, for 2 years. Find the final amount and the interest earned, to the nearest cent.
Answer: Amount $1,929.38; interest $179.38
- A = P(1 + r)n = $1,750.00 × (1 + 0.05)2
- = $1,750.00 × 1.1025
- ≈ $1,929.38
- Interest = $1,929.38 − $1,750.00 = $179.38
7.$4,000.00 is invested at 4% per year, compounded yearly, for 2 years. Find the final amount and the interest earned, to the nearest cent.
Answer: Amount $4,326.40; interest $326.40
- A = P(1 + r)n = $4,000.00 × (1 + 0.04)2
- = $4,000.00 × 1.0816
- ≈ $4,326.40
- Interest = $4,326.40 − $4,000.00 = $326.40
8.$5,750.00 is invested at 3% per year, compounded yearly, for 3 years. Find the final amount and the interest earned, to the nearest cent.
Answer: Amount $6,283.18; interest $533.18
- A = P(1 + r)n = $5,750.00 × (1 + 0.03)3
- = $5,750.00 × 1.092727
- ≈ $6,283.18
- Interest = $6,283.18 − $5,750.00 = $533.18
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